Answer:
The correct answer is: No, it may not decrease the humanity of production in organizations.
Explanation:
To begin with, the term known as <em>''humanity of production'' </em>refers to that human element that gives to the company its capability of leadership and other human abilities. Moreover, when it comes to the big data analytics those programs would not decrease the humanity of production because in order to create all those programs and in order to read all the information that those programs give and to use it and implement there will be a need of using human capital to complete the whole objective. So therefore that human will be as need as machines.
Answer:
The answer is "The group of a range of age, color, sexual orientation, financial backgrounds, employment and age differences".
Explanation:
In the given-question, the above answer is correct because the team represents a wide community of gender, ethnicity, gender identity, income levels, academic attainment, and also includes the disparities across generations, although diversity spans race and gender, and presentation must be granted to all types of people, that's why the diversity is a big factor in the visit.
Answer: Option (c) is correct.
Explanation:
Given that,
Round off the values of items to the nearest half dollar are as follows:
Item 1 = $2.00
Item 2 = $1.00
Item 3 = $3.50
Item 4 = $10.00
Item 5 = $6.00
Estimated total cost of items = Item 1 + Item 2 + Item 3 + Item 4 + Item 5
= $2.00 + $1.00 + $3.50 + $10.00 + $6.00
= $22.50
Hence, nearest value is $22.50.
Therefore, option (c) is correct.
Answer:
Instructions are listed below.
Explanation:
Giving the following information:
Kern Company deposited $1,000 in the bank on January 1, 2017, earning 8% interest. Kern Company withdraws the deposit plus accumulated interest on January 1, 2019.
We need to use the following formula:
FV= PV*(1+i)^n
A) i= 0.08 n=2
FV= 1000*(1.08^2)= $1,166.4
B) i= 0.08/2= 0.04 n= 4
FV= 1,000*(1.04^4)= $1,169.86
C) i= 0.02 n= 8
FV= 1,000*(1.02^8)= $1,171.66
Answer:
The answer is This should be possible in O(m+n) with BFS.
Explanation:
Give us a chance to take your chart G. Complete a BFS on the diagram. Check every one of the hubs in the diagrams as visited as normal with BFS. Rather than adding only hubs to the line in the DFS include hubs in addition to number of incoming ways. On the off chance that a hub that has been visited ought to be included disregard it. On the off chance that you discover a hub again which is as of now present in your line don't include it once more, rather include the checks together. Proliferate the depends on the line while including new hubs when you experience the last hub i.e the goal hub the number that is put away with it is the quantity of briefest ways in the diagram.
