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ANTONII [103]
2 years ago
5

Dominic went into a movie theater and bought 2 drinks and 5 candies, costing a total of $29.25. Colton went into the same movie

theater and bought 8 drinks and 7 candies, costing a total of $61.75. Determine the price of each drink and the price of each candy.
Mathematics
1 answer:
natali 33 [55]2 years ago
4 0

Answer: Each candy costs \$4.25 and each drink costs \$4

Step-by-step explanation:

We are told Dominic bought 2 drinks and 5 candies, costing a total of \$29.25:

2d+5c=\$29.25 (1)

Then, we are told Colton bought 8 drinks and 7 candies, costing a total of \$61.75:

8d+7c=\$61.75 (2)

Now we have a system with two equations ans two unknowns. Let's solve it:

Multiplying (1) by -4:

-8d-20c=-\$117 (3)

Summing (2) and (3):

-13c=-\$55.25 (4)

Isolating c:

c=\$4.25 (5) This is the cost of each candy

Substituting (5) in (1):

2d+5(\$4.25)=\$29.25 (6)

Isolating d:

d=\$4 (7) This is the cost of each drink

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Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

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Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
2 years ago
What is the area of the shaded region?
azamat

Answer:

(25\pi\ -24)\ cm^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

so

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

where r is the radius of the circle

In this problem we have

r=5\ cm

substitute

A=\pi (5)^{2}

A1=25\pi\ cm^{2}

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The area of the two isosceles triangles is equal to

A=2[\frac{1}{2}bh]=bh

we have

b=6\ cm

h=5-1=4\ cm

substitute

A2=6*4=24\ cm^{2}

Find the area of the shaded region

A1-A2=(25\pi\ -24)\ cm^{2}

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