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Kipish [7]
2 years ago
14

Let x1, x2, and x3 be 0 - 1 variables whose values indicate whether the projects are not done (0) or are done (1). Which answer

below indicates that at least two of the projects must be done?a.x1+ x2+ x3>2b.x1+ x2+ x3<2c.x1+ x2+ x3= 2d.x1- x2= 0
Mathematics
1 answer:
Sav [38]2 years ago
4 0

Answer:

Correct statement: a. x₁ + x₂ + x₃ > 2

Step-by-step explanation:

The variables <em>x</em>₁, <em>x</em>₂ and <em>x</em>₃ takes value 0 if the projects are not done and 1 if the projects are done.

Consider that at least two projects are done, i.e. 2 or more projects are done.

This can happen in:

x₁ = 0, x₂ = 1 and x₃ = 1

x₁ = 1, x₂ = 0 and x₃ = 1

x₁ = 1, x₂ = 1 and x₃ = 0

x₁ = 1, x₂ = 1 and x₃ = 1

The statement (x₁ + x₂ + x₃ > 2) will be true only when all the variables takes the value 1.

This statement implies that 2 projects are definitely done.

Thus, the correct statement is (a).

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Graphs of the following equations are straight lines except :
scoundrel [369]

Answer:

D

Step-by-step explanation:

6 0
2 years ago
The enrollment in college a may be modeled by y = 0.051x + 0.470, and the enrollment in college b may be modeled by y = –0.041x
sasho [114]
The first equation represents the enrollments of college A
The second equation represents the enrollments of college B
if you let two equation equal to each other, you can understand them as the enrollments of college A and college B at "x" year.

0.051x + 0.470 = -0.041x + 1.850
0.051x + 0.041x = 1.850 - 0.470
0.092x = 1.38
x = 1.38/0.092 = 15 years from 1990, 1990 + 15 = 2005 
both equations represents the enrollments, but for specific the year of 2005, they have the same enrollments. You can either plug 2005 in the first or second equation, the answer will come out the same.
y = 0.051(2005) + 0.470 = 102.745 thousands of enrollments. It's awkward to say it this way, you can multiply 102.745 by 1000.
==> 102.725 * 1000 = 102725 enrollements 
===================================================================
The year of 2005 college A and college B both have the same enrollments of 102725.  

5 0
2 years ago
Suppose in the next year, 2007, College D's expenses and enrollment remain about the same, but in addition to their current reve
Olin [163]

This question is incomplete, here is the complete question:

Suppose in the next year, 2007, College D's expenses and enrollment remain about the same, but in addition to their current revenues, they receive an additional $50,000,000 grant. This would allow them to reduce average tuition by how much?

A) $1388.89

B) $3571.43

C) $5555.56

D) $9500.00

E) $25888.89

number of students = 36,000

Answer: A) $

1388.89

Step-by-step explanation:

the college received additional grant which is $50,000,000

and the number of students is 36,000,

and we also know that expenses and enrollment remained the same.

So if we have more money (grants) and nothing changed (expenses remain the same)

dividing the grant by the number of students will show just how much the average tuition fee would be reduced

therefore R = G/n

R = 50,000,000 / 36000

R = 1,388.888 ≈  $1388.89

7 0
2 years ago
Q is in the interior of angle ROS S in the interior of angle QOP. P is in the interior of angle SOR. S is in the interior of ang
MrMuchimi

∠ROT=160°

∠SOT=100°

Now ∠SOR= ∠ROT - ∠SOT

∠ SOR = 160°-100°

∠ SOR =60°

It is given that measure of angle ROQ to equals the measure of angle QOS equals the measure of angle POT.

∠SOQ + ∠QOR = 60°

But ∠SOQ = ∠QOR

2∠SOQ=60°

∠SOQ=60°÷2

∠SOQ =30°

Also ∠POT=∠SOQ=∠ROQ=30°


3 0
2 years ago
On a sheet of paper, you have 100 statements written down. the first says, "at most 0 of these 100 statements are true." the sec
Yuki888 [10]
I would go with the second statement is true because if all of the other ones mentioned in the problem had something that would not work either the one before or after would make the statement false excepted for statement two
4 0
2 years ago
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