Question:
The image of the question is attached below.
Answer:
Volume of the bench = 528 cubic inches
Solution:
Side of the cube = 4 inch
Volume of a cube = side × side × side
= 4 inch × 4 inch × 4 inch
Volume of a cube = 64 cubic inches
Volume of 2 cubes = 2 × 64 cubic inches
Volume of 2 cubes = 128 cubic inches
Length of the prism = 25 inch
Breadth of the prism = 4 inch
Height of the prism = 8 – 4 = 4 inch
Volume of the rectangular prism = length × breadth × height
= 25 inch × 4 inch × 4 inch
Volume of the rectangular prism = 400 cubic inches
Volume of the bench = volume of 2 cube + volume of the rectangular prism
= 128 cubic inches + 400 cubic inches
Volume of the bench = 528 cubic inches
Hence volume of the bench is 528 cubic inches.
Answer:
Step-by-step explanation:
The train uses
If you reduce that you get that the train uses
To find the slope of the line, we will use the 2 points on the coordinate plane where the graph goes through: (0, 0) and (400, 200)
Applying the slope formula:
Answer:
a) 1.88% percent of the runners have heart rates above 130.
b) 50% percent of the nomrunners have heart rates above 130.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
(a) What percent of the runners have heart rates above 130?
In a study of exercise, a large group of male runners walk on a treadmill for six minutes. Their heart rates in beats per minute at the end vary from runner to runner according to the N(104,12.5) distribution. This means that .
This percentage is 1 subtracted by the pvalue of Z when .
has a pvalue of 0.9812.
This means that 1-0.9812 = 0.0188 = 1.88% percent of the runners have heart rates above 130.
(b) What percent of the nonrunners have heart rates above 130?
The heart rates for male nonrunners after the same exercise have the N(130, 17) distribution. This means that .
This percentage is 1 subtracted by the pvalue of Z when .
has a pvalue of 0.5000.
This means that 1-0.50 = 0.50 = 50% percent of the nomrunners have heart rates above 130.