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ioda
2 years ago
11

HELP QUICK I NEED TO KNOW THIS Kiva’s family is moving and he helps by carrying a 21-pound box to the truck. It is 65% lighter t

han the box that his father carries to the truck. What is the weight of the box that Kiva's father carries?
Mathematics
1 answer:
Leokris [45]2 years ago
7 0

Answer:

Therefore the weight of the box that Kiva's father carries is 60 pounds.

Step-by-step explanation:

The weight of the box carried by Kiva is 21 pounds.

Let the weight of the box carried by Kiva's father be y pounds.

The weight of box carried by Kiva is 65% lighter than the weight of the box carried by Kiva's father

Therefore we can write

( 1 - \frac{65}{100} ) y = 21\hspace{0.2cm} \Rightarrow \hspace{0.2cm}  0.35 y = 21\hspace{0.2cm} \therefore \hspace{0.2cm}  y =\hspace{0.2cm} \Rightarrow \hspace{0.2cm} 60\hspace{0.1cm}pounds

Therefore the weight of the box that Kiva's father carries is 60 pounds.

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A glass bead has the shape of a rectangular prism with a smaller rectangular prism removed. What is the volume of the glass that
olganol [36]

The volume of the removed portion is 35 cm³.

Step-by-step explanation:

Given,

The length× width× height (L×B×H) of the outer part = 3 cm×3 cm×7 cm

The length× width× height (l×b×h) of the inner part = 2 cm×2 cm×7 cm

To find the volume of the removed portion.

Formula

The volume of the removed portion = volume of outer part - volume of inner part

Volume of rectangular prism = l×b×h

Now,

Volume of outer part = 3×3×7 cm³ = 63 cm³

Volume of inner part = 2×2×7 cm³ = 28 cm³

Hence,

The volume of the removed portion = 63-28 cm³ = 35 cm³

4 0
2 years ago
Read 2 more answers
What is the true solution to the equation below?
jarptica [38.1K]

Answer:

Step-by-step explanation:

some rules of logarithmic function

ln(a) - ln(b)=ln(\frac{a}{b})

e^{ln(a)}=a

ln(a)^{n}=nln(a) vice-versa nln(a)=ln(a)^{n}

If ㏑(a) = ㏑(b), then a = b

∴ 2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)

Use the 2nd rule to simplify it

e^{ln(2x)}=2x\\e^{ln(10x)}=10x\\

2㏑(2x) - ㏑(10x) = ㏑(30)

Use the 3rd rule in the 1st term

∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)

∴ ㏑(4x²) - ㏑(10x) = ㏑(30)

- Use the 1st rule with the left hand side

ln(4x^{2})-ln(10x)=ln(\frac{4x^{2}}{10x})\\\\ln(\frac{4x^{2}}{10x})=ln(30)\\\\ \frac{4x^{2}}{10x}=\frac{2x}{5}=\frac{2}{5}x\\\\ ln(\frac{2}{5}x)=ln(30)

Use the 4th rule

\frac{2}{5} x = 30

Multiply both sides by 5

∴ 2 x = 150

- Divide both sides by 2

∴ x = 75

The value of x = 75

3 0
2 years ago
a table to summarize costs Sheri gives her dog groomer a generous tip. Using a benchmark fraction and the table, estimate the ti
zvonat [6]

Your Answer Will Be 15$

8 0
2 years ago
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The parallel dotplots below display the girths (belly
liraira [26]

Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

8

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0
2 years ago
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho
abruzzese [7]

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (175) + 0.977* (175)

                                    = 787.5 + 170.975

                                    = 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

                                    = 4.5* (170) + 0.977* (170)

                                    = 765 + 166.09

                                    = 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

                                                                 = 958.475 - 931.09

                                                                 = 27.385 cm.

8 0
2 years ago
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