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2 years ago

Janet can read 3.6 pages of a book in a minute. If she read for 2.71 minutes. How much would have she had read

Mathematics

1 answer:

Aliun [14]2 years ago

8 0

Answer:

9.76 pages

Step-by-step explanation:

multiply 3.6 times 2 to get 7.2. Then multiply 3.6 times .71 to get 2.56 then add 7.2 and 2.56 to get <u>9.76</u> as your answer.

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Write the expression n.n.p.p.r.r.r

borishaifa [10]

Answer:

2n.2p.3r

Step-by-step explanation:

idk

7 0

2 years ago

At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017

Anarel [89]

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

4 0

2 years ago

The following function represents the production cost f(x), in dollars, for x number of units produced by company 1:

tamaranim1 [39]

Company 1: f(x) = 0.25x² - 8x + 600
f(6) = 0.25(6²) - 8(6) + 600 = 9 - 48 + 600 = 561
f(8) = 0.25(8²) - 8(8) + 600 = 16 - 64 + 600 = 552
f(10) = 0.25(10²) - 8(10) + 600 =  25 - 80 + 600 = 545
f(12) = 0.25(12²) - 8(12) + 600 = 36 - 96 + 600 = 540
f(14) = 0.25(14²) - 8(14) + 600 = 49 - 112 + 600 = 537

company 2:
  x   g(x)
6 862.2
  8 856.8
10 855
12 856.8
14 862.2

Based on the given information, the minimum production cost of company 2 is greater than the minimum production cost of company 1.

7 0

2 years ago

Read 2 more answers

A random sample from a normal population is obtained, and the data are given below. Find a 90% confidence interval for . 114 157

melamori03 [73]

Answer:

$103.160 \leq \sigma \leq 187.476$

And the upper bound rounded to the nearest integer would be 187.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

Data given: 114 157 203 257 284 299 305 344 378 410 421 450 478 480 512 533 545

The confidence interval for the population variance $\sigma^2$ is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^{17} (x_i -\bar x)^2}{n-1}}$

And in order to find the sample mean we just need to use this formula:

$\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample mean obtained on this case is $\bar x= 362.941$ and the deviation s=132.250

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=17-1=16$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a tabel to find the critical values.