Question

Write code that prints: Ready! firstNumber ... 2 1 Run! Your code should contain a for loop. Print a newline after each number and after each line of text Ex: firstNumber = 3 outputs:

Answer 1

Answer:

//This program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare Variable

int firstNumber;

// Accept Input for firstNumber

cin>> firstNumber;

// Print firstNumber

cout<<"firstNumber = "<<firstNumber<<endl;;

//Start Loop

for(int i = firstNumber - 1; firstNumber>0; firstNumber--)

{

// Print iteration value

cout<<firstNumber<<endl;

}

// Print Run! at the end

cout<<"Run!";

return 0;

//End of Program

}

Answer 2

Complete Question:

Write code that prints: Ready! userNum ... 2 1 Blastoff! Your code should contain a for loop. Print a newline after each number and after each line of text Ex: userNum = 3 outputs: Ready! 3 2 1 Blastoff!

Answer:

public class TestClock {

   public static void main(String[] args) {

       int userNum= 3;

       System.out.print("Ready! "+userNum+" ");

       for (int i=userNum;i>1; i--){

           userNum--;

           System.out.print(userNum+" ");

       }

       System.out.println("Blasoff!");

   }

}

Explanation:

1. Create and initialize userNum
2. Use System.out.print to print the sequence ("Ready! "+userNum+" ") on same line
3. use for statement with this condition for (int i=userNum;i>1; i--) decremeent userNum by 1 after each loop iteration and print userNum on same line
4. outside the for loop print "Blasoff!"

Answer 3

#include <iostream>
using namespace std;

int main() {
int firstNumber;
int i;

cin >> firstNumber;

for(i = firstNumber; i>0; --i) {
if (i == firstNumber && i>0) {
cout << "Ready!" << endl;
cout << firstNumber << endl;
}
else if (i!= firstNumber && i>0){
firstNumber = (firstNumber-1);
cout << firstNumber << endl;
}
}
if (firstNumber<= 0){
cout << "Ready!" << endl;
}
cout << "Run!" << endl;
return 0;
}</iostream>