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FinnZ [79.3K]
2 years ago
12

The stock market quote shows a three-year price graph for a 3-D printing company. What might an investor expect regarding the st

ock price
or a price change in five days?​

Mathematics
1 answer:
ipn [44]2 years ago
8 0

According to the graph in this picture, the prices of of the company has been falling since the last three years, so a sudden rise is not expected but it will not change much in the next five days also.

<u>Explanation:</u>

To understand the pattern of the prices of the printing company in the last three years, a look at the graph should be made. According to the graph, there has been fall in the price of the stock of this printing company. It has seen a continuous fall.

The graph shows no sudden rise in the price of the stock, so the investor should not expect any sudden rise in the prices of the stock of this company. Any how five days is a very short span of showing any change in the price of the stock.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Tanzania [10]

Answer:

Approximately, 159 men weighs more than 165 pounds and  159 men weighs less than 135 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 150 pounds

Standard Deviation, σ = 15

We are given that the distribution of weights of 1000 men is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P( men weighing more than 165 pounds)

P(x > 165)

P( x > 165) = P( z > \displaystyle\frac{165 - 150}{15}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 165) = 1 - 0.8413 = 0.1587 = 15.87\%

Approximately, 159 men weighs more than 165 pounds.

P(men weighing less than 135 pounds)

P(x < 135)

P( x < 135) = P( z < \displaystyle\frac{135 - 150}{15}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 135) = 0.1587 = 15.87\%

Approximately, 159 men weighs less than 135 pounds.

6 0
2 years ago
The following are the hypotheses for a test of the claim that college graduation statue and cola preference are independent. H0:
Shkiper50 [21]

Answer:

\chi^2 = 0.579

And the critical value for the significance level used is:

\chi^2_{crit}= 5.991

Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent

Step-by-step explanation:

For this case we want to test the following hypothesis:

Null hypothesis: College graduation status and cola preference are independent

Alternative hypothesis: College graduation status and cola preference are dependent

For this case we got a calculated statistic of:

\chi^2 = 0.579

And the critical value for the significance level used is:

\chi^2_{crit}= 5.991

Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent

7 0
2 years ago
Mason cuts a giant circular cookie into 5 equal pieces. Which statements are true about the angle measures of the pieces? Select
Annette [7]

Answer:

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3 0
2 years ago
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jasenka [17]
Each pencil will cost $0.25
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As part of Kayla's exercise program,she either runs 6miles/day or rides her bike 10 miles/day.Her new goal is to cover a minimum
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