Answer:
III. Condensation of chromosomes begins.
I. Synapsis occurs.
II. Crossing-over is completed.
IV. Separation of homologous chromosomes begins
Explanation:
The prophase I of meiosis I begins with the condensation of chromosomes. The process of compaction makes the individual chromosomes visible and the stage is called leptotene.
Leptotene is followed by zygotene of prophase I during which the homologous chromosomes are paired together. The process is mediated by the synaptonemal complex. As the homologous chromosomes are paired, each pair is visible as a tetrad as each of the chromosomes of a pair has two sister chromatids.
The exchange of part of chromatids occurs during crossing over. Crossing over is the event of the pachytene stage of prophase I. After crossing over, the homologous chromosomes begin to separate from each other during diplotene but stay paired at the points of crossing over. These points are called chiasmata. Diakinesis of prophase I is marked by the dissolution of chiasmata.
<span>T he type of selection that favored progressively larger brain size in human evolution is
</span>directional selection. Directional selection is a type of natural selection (besides stabilizing selection, disruptive selection, kin selection,..)<span> in which an extreme phenotype is favored over other phenotypes. Because progressively larger brain size is an extreme phenotype this is a directional selection.</span>
Answer:
Some species will develop adaptations to survive in the deforested land.
Some populations will migrate out of the deforested area.
Explanation:
The deforested land will be able to support large trees eventually in the future, and animals cannot instantly adapt to anything.
Therefore, the most logical answers are populations will migrate to forest lands and species will eventually develop adaptations to help them in the newly deforested land.
I hope this helps! :)
Answer:
2(8x^2-13x+10)
Explanation:
There are 5 angle s in a pentagon and we are assuming are pentagon is a regular one so the angles are all congruent.
Let's let A represent the measurement of one of the those angles in our pentagon.
The sum of our angles in our pentagon would then be A+A+A+A+A or 5A.
But we are also given that this equals 40x^2-65x+50.
So that means 5A=40x^2-65x+50.
If we divide both sides by 5 we can find what one of our angles is in terms of x. So let's do that A=8x^2-13x+10.
So we want to know the sum of two our angles, we want to know what is A+A or 2A. 2A=2(8x^2-13x+10). To obtain that I just multiplied both sides of A=8x^2-13x+10 by 2.
Answer:
the concentration of the solute is lower inside the cell than outside it
Explanation:
This question depicts the process of ACTIVE TRANSPORT, which is the movement of a substance against concentration gradient, hence, requires energy input (ATP) to occur. In this case, transporting a solute from inside an animal cell to the extracellular fluid across the cell membrane always requires energy.
This is because the concentration of solute inside the cell is much lower than that of the extracellular fluid, hence, to move the solutes against this concentration gradient (low to high), energy in form of ATP is required.
