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goldenfox [79]
2 years ago
13

Very often in data science, we are interested in understanding how values change with time. Use np.diff and np.max (or just max)

to calculate the largest annual change in population between any two consecutive years.
Computers and Technology
1 answer:
Stels [109]2 years ago
6 0

Answer:

Explanation:

import numpy as np

#we define the function that takes year1 and year2 array values and return the maximum of the difference.

def max_diff(year1, year2):

#we pass the difference along the array into diff

diff = np.diff(year1, year2)

#then we take the max value

max = np.argmax(diff)

return max

#the function can be called by initializing

max_val = max_diff(year1_array, year2_array)

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Assume that name has been declared suitably for storing names (like "Misha", "Emily" and "Sofia"). Assume also that stdin is a v
zaharov [31]

Answer:

// program in java.

import java.util.*;

// class definition

class Main

{// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // object to read input

Scanner scr=new Scanner(System.in);

 // ask to enter name

System.out.print("Enter Your name: ");

 // read name from user

String NAME=scr.nextLine();

// print message

System.out.println("Greetings,"+NAME);

     

   }catch(Exception ex){

       return;}

}

}

Explanation:

Read name from user with the help of scanner object and assign it to variable "NAME".Then print a Greetings message as "Greetings,NAME" where NAME will be  replaced with user's input name.

Output:

Enter Your name: Rachel                                                                                                    

Greetings,Rachel

5 0
2 years ago
15. It is the process of capturing data or translating information to recording format
Helen [10]

Answer:

A Documentation, hope this helps.

5 0
2 years ago
. Question 2 Fill in the blank: R Markdown notebooks can be converted into HTML, PDF, and Word documents, slide presentations, a
Levart [38]

R markdown notebook describes a notebook format in R programming which supports R programmers to run codes while also writing documents or explanation alongside. Hence, the missing option is Dashboard.

  • R markdown may be compared to jupyter notebooks which also supports writing in markdown language.

  • The R markdown notebooks can be created using the R studio, which allows the conversion notebooks of these notebooks into several different formats including the creation of dashboards.

Hence, R markdown notebooks can be converted to <em>HTML</em><em> </em><em> </em><em> </em><em>PDF</em><em>,</em><em> </em><em>word</em><em> </em><em>document</em><em>,</em><em> </em><em>slide</em><em> </em><em>presentation</em><em> </em><em>and</em><em> </em>dashboards.

Learn more :brainly.com/question/25575402

3 0
2 years ago
Gwen recently purchased a new video card, and after she installed it, she realized she did not have the correct connections and
g100num [7]

Answer:

A. 8-pin PCI-E connector.

F. 6-pin PCI-E connector.

Explanation:

The video card is a peripheral hardware component in a computer system that is used to run videos and graphic files, providing the required memory, runtime and bandwidth.

The PCI-e or peripheral component interconnect express is a connector or expansion slot used specifically for adding and powering video cards on a computer system.

7 0
2 years ago
Problem 1a. Write a function named hasFinalLetter that takes two parameters 1. strList, a list of non-empty strings 2. letters,
mash [69]

Answer:

The answer is the programming in Python language has strings and characters that has to be declared in the method.

Explanation:

#method

def hasFinalLetter(strList,letters):

output = #output list

#for every string in the strList

for string in strList:

#findout the length of each string in strList

length = len(string)

#endLetter is last letter in each string

endLetter = string[length-1]

#for each letter in the letters list

for letter in letters:

#compare with endLetter

#if we found any such string

#add it to output list

if(letter == endLetter):

output.append(string)

#return the output list

return output

#TestCase 1 that will lead to return empty list

strList1 = ["user","expert","login","compile","Execute","stock"]

letters1 = ["a","b","y"]

print hasFinalLetter(strList1,letters1)

#TestCse2

strList2 = ["user","expert","login","compile","Execute","stock"]

letters2 = ["g","t","y"]

print hasFinalLetter(strList2,letters2)

#TestCase3

strList3 = ["user","expert","login","compile","Execute","stock"]

letters3 = ["k","e","n","t"]

print hasFinalLetter(strList3,letters3)

8 0
2 years ago
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