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2 years ago

2x-4y=20 what is the value of y

Mathematics

2 answers:

ra1l [238]2 years ago

6 0

Answer: 20-2x/-4

Step-by-step explanation:

To actually solve for y as a number, you need two equations.

For this case move the 2x to the other side, making the equation -4y=20-2x.

Then divide by -4 on each side making the equation y=20-2x/-4.

Phantasy [73]2 years ago

5 0

Answer:

y = 20-2x /-4

Step-by-step explanation:

Given 2x - 4y =20

y ?

Subtract 2x from both sides of the equation

2x - 2x -4y = 20 - 2x

-4y = 20 - 2x

Divide both sides by -4

-4y/-4 = 20-2x / -4

y = 20-2x /-4

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riadik2000 [5.3K]

Answer:

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Step-by-step explanation:

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2 years ago

A 32 foot ladder is leaning against a building and forms a 29.37 angle with the ground how far away from the building is the bas

BARSIC [14]

Answer:

the base of the ladder is 27.89 ft away from the building

Step-by-step explanation:

Notice that this situation can be represented with a right angle triangle. The right angle being that made between the ground and the building, the ladder (32 ft long) being the hypotenuse of the triangle, the acute angle of $29.37^o$ being adjacent to the unknown side we are asked about (x). So, we can use the cosine function to solve this:

$cos(\theta)=\frac{adjacent}{hypotenuse} \\cos(29.37^o)=\frac{x}{32\,\,ft}\\32 \,\,cos(29.37^o)\,\,ft=x\\x=27.887\,\,ft$

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6 0

2 years ago

Read 2 more answers

Three snack bars contain 1/5, 0.22, and 19% of their calories from fat. Which snack bar contains the least amount of calories fr

BabaBlast [244]

Converting all values to decimal, we have
1/5 = 0.2
19% - 19/100 = 0.19

Therefore the snack that contains 19% has the least amount of calories from fat.

4 0

2 years ago

Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real n

e-lub [12.9K]

Answer:

See Below

Step-by-step explanation:

The function is a piecewise function defined as:

$N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.$

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

$\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600$

This means the maximum number of fish at this pond is 1600, no matter how long it goes on.

A function is continuous at a point if we have the limit and the functional value at that point same.

Functional value at t = 8 is (we use 2nd part of equation):

$\frac{200+80t}{2+0.05t}\\\frac{200+80(8)}{2+0.05(8)}\\=350$

We do have a value and limit also goes to this as t approaches 8.

So, function is continuous at t = 8

We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

$N(t)=25t+150\\250=25t+150\\25t=250-150\\25t=100\\t=4$

The time is 4 years when the number of fishes in the pond is 250

6 0

2 years ago

A certain ferry moves up and down a river between Town A and B. It takes the ferry two hours to travel to Town A and only an hou

Y_Kistochka [10]

Answer:

The distance between two cities is 60 miles.

Step-by-step explanation:

Time taken to travel from B to A = 2 hours

Time taken to travel from A to B = 1.5 hours

Current speed = 5 mph

Let the speed of ferry in still water = u mph

When the ferry moves with the current, it will taken lesser time (i.e. A to B) and when it moves against the current it will take more time (i.e. B to A).

Let the distance between the two cities A and B = D miles

While moving with the current, speed = $(u+5)\ mph$