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2 years ago

Ms. Fox asked her class “Is the sum of 4.2 and √2 rational or irrational?” Patrick answered that

1 answer:

3 0

Patrick is correct because √2 is irrational (It is a real number that can't be expressed as a ratio), and even if 4.2 is added, the sum still won't be able to be expressed as a ratio √2=approx. 1.41421, and √2 +4.2=approx.5.61421. The only change in the number is in the first two digits.

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find the balance in the account. $2,400 principal earning 2%, compounded annually, after 7 years $2,736.00 $2,756.85 $307,200.00

Alex17521 [72]

The future worth (F) of the current investment (P) that has an interest (i) that is compounded annually is calculated through,
F = P x (1 + i)^n
where n is the number of compounding period. Substituting the given values,
F = ($2,400) x ( 1+ 0.02)^7 = $2,756.85
Thus, the future worth is approximately $2,756.85. The answer is the second choice.

3 0

2 years ago

Carl lives in an apartment and pays the following expenses each month: electric bill, $34.60; TV streaming service, $24.99; and

Vesna [10]

$34.60 rounds to $35
$24.99 rounds to $25
$527.85 rounds to $528

Now add the rounded numbers together:
$35
$25
$528
————-
$588.00 (estimated monthly expenses)

8 0

2 years ago

Jesse has a storage container in the shape of a right rectangular prism. The volume of the container is 43.875 cubic meters, the

AVprozaik [17]

All you have to do is divide the volume of the container (43.875) by 5 (length) and 3.9 (width) because the formula for the volume of a rectangular prism is V=lwh. So the answer/height of the storage container is 2.25 meters

8 0

2 years ago

Read 2 more answers

Before the distribution of certain statistical software, every fourth compact disk (CD) is tested for accuracy. The testing proc

lilavasa [31]

Answer:

a) For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

$P(R) =\frac{1}{4} =0.25$

The failure probability for each program are given by:

$P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01$

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

$P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932$

So then the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

And if we use the fact that we have 4 possible test the true probability of interest would be:

$P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017$

b) $p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))$

And replacing we got:

$p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484$

c) From part a we now that the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

So then if we have 100 CDs the expected number of rejected Cd's are:

$100*0.068= 6.8 \approx 7$

Step-by-step explanation:

Part a

For this case we have 4 programs so then if we define the event R that a CD is tested we have the following probability for each test:

$P(R) =\frac{1}{4} =0.25$

The failure probability for each program are given by:

$P(F_1) = 0.01 , P(F_2) = 0.03 , P(F_3) = 0.02 , P(F_4) = 0.01$

For this case we assume that each test is independet form the others.

We can calculate the probability that all 4 programs works properly like this:

$P(4 work) = (1-0.01)*(1-0.03)*(1-0.02)*(1-0.01)= 0.932$

So then the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

And if we use the fact that we have 4 possible test the true probability of interest would be:

$P(R \cap F) = P(R)*P(F) = 0.25*0.068=0.017$

Part b

For this case we want the probability that it failed program 2 or 3

So then we can find this probability like this:

$p= P(F'_1) P(F'_4) *(1- P(F'_2)*P(F'_3))$

And replacing we got:

$p =(1-0.01)*(1-0.01) *[1- (1-0.03)(1-0.02)]= 0.99*0.99*[1- 0.97*0.98]= 0.0484$

Part c

From part a we now that the probability that any program fails would be given by:

$P(F) = 1- 0.932= 0.068$

So then if we have 100 CDs the expected number of rejected Cd's are:

$100*0.068= 6.8 \approx 7$

3 0

2 years ago

luke paid 30 percent less for a used car than its original price of $3,500. how much did luke pay for the car?

serg [7]

Answer:

Im not sure ok

Step-by-step explanation:

Im trying to solve too

5 0

2 years ago

Read 2 more answers