Question

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Over b cubed minus 2 EndFraction?

Answer 1

Answer:

$b=0\: or\: b=4$

Step-by-step explanation:

The given equation is $\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

By cross multiplication, we get;

$5(b^3-2)=2(3b^3-2b^2-5)$

We expand to get:

$5b^3-10=6b^3-4b^2-10$

Combine like terms to get:

$6b^3-5b^3-4b^2-10+10=0$

$b^3-4b^2=0$

Factor to get:

$b^2(b-4)=0$

This implies that:

$b=0\: or\: b=4$

Answer 2

Answer:

C. b = 0 and b = 4

Step-by-step explanation:

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Over b cubed minus 2 EndFraction?

b = –4 and b = 0

b = –4

b = 0 and b = 4

b = 4