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Aleksandr [31]
1 year ago
15

Theoretical and experimental measurements show that in many cases, the contributions of ionic and hydrogen-bonding interactions

to ΔH for protein folding are close to zero. Provide an explanation for this result. (Hint: Consider the environment in which protein folding occurs.)
The formation of favorable ______ ionic or ________ interactions in a _________ protein replace interactions between solvent (water) and the ionic species (or _________donors and acceptors) in the _________ state. The favorable ΔH obtained by formation of ____________ bonds in the ___________ protein is offset by the energy required to ___________ many interactions, with solvent going from the ________ to the ________ state.

Fill in the blanks above using the words listed below.

H-bonding

H-bond

intermolecular

restore

unfolded

folded

C-bond

break

intramolecular

C-bonding
Biology
2 answers:
9966 [12]1 year ago
6 0

Answer:

The answer is:

The formation of favorable intermolecular ionic or H-bonding interactions in a folded protein replace interactions between solvent (water) and the ionic species (or H-bond donors and acceptors) in the unfolded state. The favorable ΔH obtained by formation of intramolecular bonds in the folded protein is offset by the energy required to break many interactions, with solvent going from the unfolded to the folded state.

Explanation:

Bad White [126]1 year ago
4 0

Answer:

The formation of favorable C-bond ionic or C-bonding interactions in a folded protein replace interactions between solvent (water) and the ionic species (or restore donors and acceptors) in the unfolded state. The favorable ΔH obtained by formation of H-bond in the H-bonding protein is offset by the energy required to break many interactions, with solvent going from the inter-molecular to the intramolecular state.

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Theodor W. Engelmann illuminated a filament of algae with light that passed through a prism, thus exposing different segments of
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Answer:

C) Bacteria congregated in these areas because these areas had the most oxygen being released.

Explanation:

Below is the full question:

Theodor W. Engelmann illuminated a filament of algae with light that passed through a prism, thus exposing different segments of algae to different wavelengths of light. He added aerobic bacteria and then noted in which areas the bacteria congregated. He noted that the largest groups were found in the areas illuminated by the red and blue light.

What did Engelmann conclude about the congregation of bacteria in the red and blue areas?

A) Bacteria released excess carbon dioxide in these areas.

B) Bacteria congregated in these areas due to an increase in the temperature of the red and blue light.

C) Bacteria congregated in these areas because these areas had the most oxygen being released.

D) Bacteria are attracted to red and blue light and thus these wavelengths are more reactive than other wavelengths.

E) Bacteria congregated in these areas due to an increase in the temperature caused by an increase in photosynthesis.

The most efficient region of white light for photosynthesis has been found to be the blue and red region of the white light. Hence, these two regions must have had the most oxygen being released because they are the regions with the highest rates of photosynthesis.

<em>Aerobic bacteria thrived better in the regions illuminated by red and blue light because these regions had the highest oxygen production as a result of having the highest rates of photosynthesis.</em>

<em>The correct option is C.</em>

3 0
1 year ago
How are histone modification enzymes (such as HATs) and chromatin remodeling complexes recruited to unmodified chromatin, and ho
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Answer:

A histone modification mechanism proliferate through a process that includes post translational modification procedure. The methylation, acetylation as well as ubiquitylation are one of the main modifiers that help in activation of silent genes and ultimately these covalently bonded histone modifiers help in regulating chromatin. The PTM has a main role in altering histone structure by these modifier's recruitment....

3 0
2 years ago
What did rosenberg and trevathan discover in their study comparing human and nonhuman primate birth?
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When comparing the birth patterns of humans and non-human primate, Rosenberg and Trevathan discovered some very clear differences:

1. The human period of labour and child birth is exceptionally long and painful compared to other non-human primates.
E.g. a human labour can last anywhere from 10-20 hours while that of a chimpanzee lasts only 2 hours.

2. Humans have the ability to walk straight, the trade off however is that it is extremely difficult and painful to give birth to a big brained human baby.
3 0
2 years ago
Read 2 more answers
A line graph has a vertical axis labeled "Average plant mass (g)^ * and a horizontal axis labeled "Herbicide (g/plant)." What in
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Answer:

The correct option is D. The average mass of plants exposed to 3 g of herbicide was 10g.

Explanation:

As the vertical axis is labelled as average plant mass, it will make the y- coordinate.

As the horizontal axis is labelled as Herbicide (g/plant), it will make the x-axis.

The coordinates for the given value are (3,10). 3 will be the value of the x- coordinate. Hence, it will show the average mass of the plant at the plotted point which will be 3 g.

10 will show the value of the y- coordinate which will be the amount of herbicide given to the plant.

Hence, Dis the correct option.

7 0
2 years ago
Based on the DNA strand below, and assuming the promoter for this gene is located to the le\, which protein sequence below does
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<h2>Protein sequence</h2>

Explanation:

  • The given sequence is of coding strand(5'-3' direction)

5’-ATGTTGAAAATGCCGTAGAGGC-3’  

  • Protein is made up of mRNA and mRNA has the same sequence as coding strand(only T is replaced by U) so the sequence of mRNA will be:

5’-AUGUUGAAAAUGCCGUAGAGGC-3’

According to the genetic code,3 bases code for one nucleotide and further nucleotide codes for amino acid,amino acids forms the base for protein

  • AUG codes for Methionine(Met)
  • UUG codes for Leucine(Leu)
  • AAA codes for Lysine(Lys)
  • AUG codes for Methionine(Met)
  • CCG codes for Proline(Pro)
  • UAG codes for stop codon(Stop)

Once the stop codon comes protein synthesis will be stopped,so the final protein sequence will be:

Met-Leu-Lys-Met-Pro-Stop

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