In the context of data patterns in a time series, a(n) _____ is a one-time variation that is explainable.

If triangle LMN has an obtuse angle at vertex M, which statements could be true? Check all that apply.

nirvana33 [79]

Answer: Triangle LMN is an obtuse triangle.

The angle at vertex L is acute.

The angle at vertex N is acute.

Step-by-step explanation:

Here, triangle LMN has an obtuse angle at vertex M,

Thus, by the definition of obtuse angle triangle LMN is an obtuse triangle,

Now, Angle M is obtuse,

⇒ 90° < m∠ M < 180°

Since, by the property of a triangle,

m∠ L + m∠ M + m∠ N = 180°

⇒ m∠ M = 180° - ( m∠ L+ m∠ N )

⇒ 90° < 180° - ( m∠ L+ m∠ N ) < 180°

⇒ 90° - 180° < - ( m∠ L+ m∠ N ) < 0

⇒ -90° < - ( m∠ L+ m∠ N ) < 0

⇒ 90° > ( m∠ L+ m∠ N ) > 0 ( Since, a - b)

⇒ 90° > m∠ L and 90° > m∠ N

⇒ Both angle L and angle N are acute.

5 0

2 years ago

Read 2 more answers

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

2 years ago

Elena bought 320 tropical fish for a museum display. She bought 7 times as many triggerfish as parrotfish. How many of each type

luda_lava [24]

X+y = 320 y = 7x ..............

3 0

2 years ago

(8.218+9.93)+(17.782+0.07)

Licemer1 [7]

First, using the order of operations(PEMDAS), you would solve what is inside the parenthesis.
(8.218 + 9.93) + (17.782 + 0.07)
(18.148) + (17.852)
18.148 + 17.852

Now, all you would have to do is add the two sums.
18.148 + 17.852 = 36

The answer would be 36.

I hope this helps!

5 0

2 years ago

Given a rectangular pyramid and a rectangular prism that have the same base and same height, how do their volumes compare? If th

Luden [163]

We know that
volume of a rectangular prism =B*h------> equation 1
where
B is the area of the base
h is the height

volume of a rectangular pyramid=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

the answer part a) is
volume of a rectangular pyramid=(1/3)*volume of a rectangular prism

Part b) If the pyramid was full of water, how much of the prism would it fill up?

the answer part b) is
If the pyramid was filled with water, the prism would only fill 1/3 of its volume

Part c) Name another pair of three-dimensional objects that have a relationship similar to this

cones and cylinders

volume of a cylinder =B*h------> equation 1
where
B is the area of the base
h is the height 

volume of a cone=(1/3)*B*h-----> equation 2
where
B is the area of the base
h is the height

substitute equation 1 in equation 2
volume of a cone=(1/3)*volume of a cylinder

4 0

2 years ago