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Musya8 [376]
1 year ago
14

Let g(x, y) = cos(x + 2y). (a) Evaluate g(2, -1). (b) Find the domain of g. (c) Find the range of g. 1. Find and sketch the doma

in of the function f(x, y) =sqrt(y-x^2)/(1-x^2) 2. Draw a contour map of the function f(x, y) = ye^-x showing several level curves. 3. Sketch both a contour map and a graph of the function f(x, y) = x^2 + 9y^2.
Mathematics
1 answer:
skelet666 [1.2K]1 year ago
4 0

Not going to do (1), (2), (3) since they are implicit from (a) and (b) and require graphs (which aren't supported on brainly).

We have g(x,y)=\cos(x+2y), that means, if plug in x=2,y=-1 we get g(2,-1)=\cos(2+2(-1))=\cos(0)=\boxed{1}.

Doman of cosine is x\in[0,1].

Hope this helps.

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2 years ago
. A high school currently has a 30% dropout rate. They’ve been tasked to decrease that rate by 20%. Find the equivalent percenta
Crazy boy [7]

Answer:

The equivalent percentage point drop = 10%

Step-by-step explanation:

The percentage point change is the difference between the final and initial values.

The percentage change is the difference between the final and initial values

divided by the initial value

It is required to decrease the dropout rate from 30% to 20%

The point change = 20 - 30 = -10 (-ve change ⇒ decrease)

The percentage change = \frac{10}{30}*100 = 33.33_%%

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Samantha walked 10 miles in 5 hours. What was her walking rate in miles per hour?
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2 years ago
On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

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