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Natali [406]
2 years ago
13

A metal rod is 25.000cm long at 25.0 degrees Celsius. When heated to 102.0 degrees Celsius, it is 25.054 cm long. What is the co

efficient of linear expansion for this metal?
Mathematics
2 answers:
inn [45]2 years ago
6 0
<span>You may deduce what it represents by analyzing the formula you just wrote.
Well, </span>the coefficient of linear expansion as the fractional change in length per degree of temperature change. 

ΔL = c x L(initial) x ΔT 

where c is the coefficient of linear expansion. You can rewrite the equation to give you c. 

c = ΔL / [L(initial) x ΔT] 

<span>Just substitute the variables and the answer will be
c = 0.000028. </span>

Now, what it represents.It may represent the extent to which the rod expands with temperature when compared to its original length. 
alekssr [168]2 years ago
6 0

α =2.81 E -5 degrees C

or 

α =2.81 x 10^ -5 degrees C

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Crop researchers plant 15 plots with a new variety of corn. The yields in bushels per acre are: 138.0 139.1 113.0 132.5 140.7 10
son4ous [18]
There is a relationship between confidence interval and standard deviation:
\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}
Where \overline{x} is the mean, \sigma is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first: 
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When we do all the calculations we find that:
\overline{x}=123.8\\ \sigma=11.84
Now we can find confidence intervals:
($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing
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2 years ago
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These are ur answers

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2 years ago
an original piece of art work is 3 feet by 2.5 feet. a reprint of the artwork is 6 inches by 5 inches. are the pieces similar? i
RoseWind [281]
For this case we observe that the dimensions of the original piece are:
 3 feet
 2.5 feet
 Let's multiply these dimensions by a scale factor k:
 3 * k
 2.5 * k
 We match the new dimensions with their respective values:
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 2.5 * k = 5
 Clearing k we have:
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 Answer:
 
The pieces are similar.
 
The ratio of their corresponding side lengths is: 
 
k = 2
3 0
2 years ago
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