Question

Ari mixed 2 cups of red grapes with cups of green grapes. He then divided the grapes into bags with cup of mixed grapes in each. How many bags of grapes will Ari have

Answer 1

Answer:

$3\frac{2}{3}$ bags of mixed grapes.

Step-by-step explanation:

Please consider the complete question.

Ari mixed 2 1/4 cups of red grapes with 1/2 cups of green grapes. He then divided the grapes into bags with 3/4 cup of mixed grapes in each. How many bags of grapes will Ari have?

To solve our given problem, we need to divide sum of red grapes and green graps by 3/4.

$\text{Cups of mixed grapes}=2\frac{1}{4}+\frac{1}{2}$

$\text{Cups of mixed grapes}=\frac{9}{4}+\frac{1}{2}$

Make a common denominator:

$\text{Cups of mixed grapes}=\frac{9}{4}+\frac{2}{4}$

$\text{Cups of mixed grapes}=\frac{9+2}{4}$

$\text{Cups of mixed grapes}=\frac{11}{4}$

$\text{Bags of mixed grapes that Ari will have}=\frac{11}{4}\div \frac{3}{4}$

Convert into multiplication problem by flipping the 2nd fraction as:

$\text{Bags of mixed grapes that Ari will have}=\frac{11}{4}\times \frac{4}{3}$

$\text{Bags of mixed grapes that Ari will have}=\frac{11}{3}$

$\text{Bags of mixed grapes that Ari will have}=3\frac{2}{3}$

Therefore, Ari will have $3\frac{2}{3}$ bags of mixed grapes.