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2 years ago

Calculate the number of oxygen atoms in 2.00 moles of Mn2O7

1 answer:

7 0

First you should know that there is seven oxygen atoms in one Mn2O7
So
2.00 moles of Mn2O7 contain 14.00 moles of oxygen...
Then you multiply this no. with Avagadro no....
from formula
Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen...

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Which milligram quantity contains a total of four significant figures

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D has a total of four significant figures.

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Movement of the ___<br> creates the London dispersion forces.

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2 years ago

Determine the number of moles in 4.21 x 10^23 molecules of CaCl2

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<h3>Answer:</h3>

0.699 mole CaCl₂

<h3>Explanation:</h3>

To get the number of moles we use the Avogadro's number.

Avogadro's number is 6.022 x 10^23.

But, 1 mole of a compound contains 6.022 x 10^23 molecules

In this case;

we are given 4.21 × 10^23 molecules of CaCl₂

Therefore, to get the number of moles

Moles = Number of molecules ÷ Avogadro's constant

= 4.21 × 10^23 molecules ÷ 6.022 x 10^23 molecules/mole

= 0.699 mole CaCl₂

Hence, the number of moles is 0.699 mole of CaCl₂

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2 years ago

The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is __________% by

amm1812

Answer:

The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass

Explanation:

2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.

We know that density is equal to ratio of mass to volume.

Here density of solution is 1.01 g/mL.

So mass of 1000 mL solution = ( $1.01\times 1000$ ) g = 1010 g

molar mass of NaCl = 58.44 g/mol

So mass of 2.23 moles of NaCl = ( $2.23\times 58.44$ ) g = 130.3 g

% by mass is ratio of mass of solute to mass of solution and then multiplied by 100.

Here solute is NaCl.

So % by mass of 2.23 M aqueous solution of NaCl = $\frac{130.0}{1010}\times 100$ % = 12.90%

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2 years ago

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Hence the species in equilibrium are:

Acetate anion: CH3COO-

Methyl ammonium cation: CH3NH3+

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