The identity of a carbonyl-containing compound has been narrowed down to three possibilities: acetamide (ethanamide), acetone (p
ropanone), or 1,1,1-trichloropropanone. 1h nmr and ir spectral data for the compound are given below. determine the structure, and thus the identity, of the compound that gives the observed data.
1 answer:
I have provided a pair of spectra, NMR and IR for one of the compounds in the question.
The NMR spectrum provides the least information, as there is only a single peak that is a singlet. All three compounds have a methyl group adjacent to a carbonyl that would appear as a singlet. However, the chemical shift is closer to 3 ppm which suggests it is being deshielded further compared to a standard carbonyl which would appear at 2 ppm. This suggests the structure is most likely 1,1,1-trichloropropanone.
Looking at the IR spectrum, we see the carbonyl stretch at approximately 1750 cm⁻¹. We also see the presence of strong stretches at 750 and 850 cm⁻¹ which are very characteristic of a C-Cl stretch. Therefore, there is enough evidence to suggest that these spectra correspond to 1,1,1-trichloropropanone.
The NMR spectrum provides the least information, as there is only a single peak that is a singlet. All three compounds have a methyl group adjacent to a carbonyl that would appear as a singlet. However, the chemical shift is closer to 3 ppm which suggests it is being deshielded further compared to a standard carbonyl which would appear at 2 ppm. This suggests the structure is most likely 1,1,1-trichloropropanone.
Looking at the IR spectrum, we see the carbonyl stretch at approximately 1750 cm⁻¹. We also see the presence of strong stretches at 750 and 850 cm⁻¹ which are very characteristic of a C-Cl stretch. Therefore, there is enough evidence to suggest that these spectra correspond to 1,1,1-trichloropropanone.
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Answer:
Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).
Explanation:
This is a chemical reaction problem.
In expressing any chemical reaction, we need to understand that there are reactants and products.
- The reactants are the species on the left hand side that are combining.
- The products are the species on the right hand side that are formed.
- Every chemical reaction is obeys the law of conservation of matter i.e equal number of matter on both sides.
Using the statement of this problem, we can deduce that;
Reactants are Fluorine gas and Calcium metal
Product is Calcium Fluoride
Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.
F₂ + Ca
→ CaF₂
We can see that equal number of atoms are on both sides of the expression.
Answer:
Negative sign says that release of heat.
Explanation:
The expression for the calculation of the heat released or absorbed of a process is shown below as:-
Where,
is the heat released or absorbed
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass = 25.2 g
Specific heat = 0.444 J/g°C
So,
Negative sign says that release of heat.