Question

You want to obtain cash by using an​ ATM, but​ it's dark and you​ can't see your card when you insert it. The card must be inserted with the front side up and the printing configured so that the beginning of your name enters first. Complete parts​ (a) through​ (c).
a. What is the probability of selecting a random position and inserting the card with the result that the card is inserted correctly? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The probability is O B. This is a trick question. There is not enough information given to determine the answer.

b. What is the probability of randomly selecting the card's position and finding that it is incorrectly inserted on the first attempt, but it is correctly inserted on the second attempt? (Assume that the same position (Type an integer or a simplified fraction.) used for the first attempt could also be used for the second attempt.) Select the correct choice below and, if necessary, fil in the answer box to complete your choice. O A. The probability is O B. This is a trick question. There is not enough information given to determine the answer.

c. How many random selections are required to be absolute sure that the card works because it is inserted correctly? Select the correct choice below and, if necessary, fill in the answer box to complete your (Type an integer or a simplified fraction.) choice. 0 A. The number of random selections required is (Type an integer or a simplified fraction.) This is a trick question. There is no finite number of attempts, because it is possible to get the wrong position every time B.

Answer 1

Answer:

Step-by-step explanation:

Given that you want to obtain cash by using an​ ATM, but​ it's dark and you​ can't see your card when you insert it. The card must be inserted with the front side up and the printing configured so that the beginning of your name enters first. Complete parts​ (a) through​ (c)

There are four positions to enter the card out of which one position is right.

a)  the probability of selecting a random position and inserting the card with the result that the card is inserted correctly=1/4 = 0.25

b) the probability of randomly selecting the card's position and finding that it is incorrectly inserted on the first attempt, but it is correctly inserted on the second attempt

= Prob of wrong insertion in I attempt * prob of trying remaining 3 positions and getting right

=$\frac{3}{4} *\frac{1}{3} \\=0.25$

c) Random selections can be 1,2,3 or atmost 4.

There cannot be more than 4.

A. The number of random selections required is four.