Kelly, the GearUp CEO, calls you into her office and says that she feels that her management team and the GearUp company as a wh
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Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh = EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl = EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh = = 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
Answer:
The overall Utility delivered to customers in a year 'U' = 6.25 X 10¹⁰Kwh
However, the average power P, required for a year, t = ? Kw
Expressing their relationship, we will have
U = P x t
Given t = 1 year = 24 x 365 hours (assume a year operation is 365 days)
t = 8760 hours
P =
P = 7134.7Kw
Hence, the average power required during the year is 7,135Kw
Now to calculate the energy used by the power plant in a year (in quads)?
Recall, Efficiency, η = Power Output/Power Input (100)
so, we have
η = P₀/P₁, given
0.45 =
P₁ = 15,855Kw
the total energy E₁ used in a year = 15,855x24x365 = 138.89MJoules
So to convert this to quads, Note;
1 quads of energy = 10¹⁵ Joules
The total energy used is 0.000000139 quads
Now to find the cubic feet of natural gas required to generate this power?
Note: 0.29Kwh of Power generated = 1 cubic feet of natural gas used
Since, the power plant generated = 62500000000Kwh
The cubic feet of natural gas used =
Hence, 2.155x10²⁰cubic feet of N.gas was used to generate this much power.