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qwelly [4]
2 years ago
13

Leah Jones is the IT manager at Rock Solid Outfitters, a medium-sized supplier of outdoor climbing and camping gear. Steve Allen

, the marketing director, has asked Leah to develop a special web-based promotion. As Steve described it to Leah, Rock Solid will provide free shipping for any customer who either completes an online survey form or signs up for the Rock Solid online newsletter. Additionally, if a customer completes the survey and signs up for the newsletter, Rock Solid will provide a $10 merchandise credit for orders of $100 or more. Leah has asked you to develop a decision table that will reflect the promotional rules that a programmer will use. She wants you to show all possibilities, and then to simplify the results to eliminate any combinations that would be unrealistic or redundant.

Computers and Technology
1 answer:
VARVARA [1.3K]2 years ago
7 0

Answer:

Step 1 : Construct the table under three conditions possible and with two possible results. A total of 8 possible rules should be provided for the three different conditions, and the table should look like the following example : attached is the discount table

Step 2 : Now the rules can be simplified, by considering the following :

a) If a consumer filled survey form AND signs up for newsletter, as in Rules 1and2, they are eligible to receive a discount when their order exceeds $100. Twoseparate rules are therefore included and the third condition (order quantity) is relevant.

b) If the customer finalizes the survey form OR signed up for the newsletter, as provided for in Laws 3, 4, 5 and 6, he or she will receive free shipments, but the purchase quantity does not matter. Therefore, such situations may be known as two separate rules where one requirement is fulfilled, but not the other.

c) If a client does not fulfill any of the requirements, as in Rules 7 and 8, the order amount shall not be applied to him or her for either free shipping or discount. It can be interpreted as one law. The simplification table is linked to this.

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Return 1 if ptr points to an element within the specified intArray, 0 otherwise.
Paladinen [302]

Answer:

int withinArray(int * intArray, int size, int * ptr) {

      if(ptr == NULL) // if ptr == NULL return 0

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      if(size == 0)

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  else  

          {

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Explanation:

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4 0
2 years ago
Give a proof for each statement.
Marrrta [24]

Answer:

  • If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
  • If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
  • The average of three real numbers is greater than or equal to at least one of the numbers.

Explanation:

1)

Suppose that  each kid has less than 12 trophies

Total trophies = 100

Maximum trophies won by one kid = 11

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total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100

2)

Suppose that  person has less than 2 cups of coffee a day

Total cups of coffee = 400

he has bought at least one cup of coffee each day

which means

total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year

3)

Average of three number = (a+ b+ c)/3

suppose that there are real numbers a, b, and c such  that all three numbers are less than the average of the three numbers.

Let m be the average (a+b+c )/3 = m. Then our assumption states that (a < m) and  (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is  defined to be (a+b+c) /3  , so a + b + c = 3m.  But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious  contradiction. Thus our claim is true

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