Question

A laboratory technician needs to make a 72​-liter batch of a 20​% acid solution. How can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired​ concentration?

Answer 1

Answer: 8 L of 100% pure acid and 64 L of 10% acid must be combined

Step-by-step explanation:

According to the dilution law,

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ = concentration of pure acid solution = 100 %

$V_1$ = volume of pure acid solution = x L

$C_2$ = concentration of another acid solution= 10%

$V_2$ = volume of another acid solution= (72-x) L

$C_3$ = concentration of resulting acid solution = 20 %

$V_1$ = volume of resulting acid solution = 72 L

Putting the values in the equation:

$100\times x+10\times (72-x)=20\times 72$

$x=8L$

Therefore, the laboratory technician must take 8 L of 100% pure acid and (72-8) = 64 L of 10% acid to get 72​-liter batch of a 20​% acid solution.

Answer 2

I hope this helps you 72.20%=(72+?).10% 72.2=72+? ?=72