Because they are autorotrophs(they make their own food)so most organisms depend on them.
Most of the marine animals have a stream lined body, which means, they have a sharp and pointed at the front. The pointed front of the organism allow to cut the resistance of the water. In case, the body is not pointed at the front and it is blunt, the water current and flow would resist the movement of the organism further. So, for the locomotion purpose, it is important to have a streamlined body. Further smooth and hair less body also decrease the resistance during the movement in the water.
Explanation:
There basically four stages of sensory pathway when an animal responds to information about its environment.
and these stages of pathway are Reception, transduction, transmission, and perception.
This is the DNA. I'm going to only use the upper strand to demonstrate what this strand would code for before and after a single bp deletion (so write it as mRNA). I will also write it how it's easier to see this which is to split them up into the 3 base codon system. Note that you don't need to know the amino acid code - you use a table to find these.
ORIGINAL (mRNA on top, Amino Acid (AA) on bottom:
5'-AGC GGG AUG AGC GCA UGU GGC GCA UAA CUG-3'
SER GLY MET SER ALA CYS GLY ALA STOP LEU
Note that the protein would stop being made at the stop codon and the LEU wouldn't matter at the end...
Now, I will remove one bp...(I bolded it up top). Rewrite the mRNA and find the corresponding AA...
NEW
5'-AGC GGG AUG GCG CAU GTG GCG CAU AAC UG-3'
SER GLY MET ALA HIS VAL ALA HIS ASN .....
Completely different amino acid sequence after the methionine (MET). The stop codon is gone...the protein would continue being translated until it reaches another stop codon...so not what was supposed to be made!
Answer:
a. The formula for finding the number of colonies in a given volume is,
CFU/ml, here CFU is the colony forming units or the number of colonies formed in a volume plated in ml × dilution
The dilution factor given in the question is 1 × 10⁻⁴ and the number of colonies given is 186. Therefore, the number of bacteria present in the given 1 ml of the milk is,
CFU/ ml = 186 / 1 × 10⁻⁴ = 186 × 10⁴.
Hence, the concentration of bacteria in the milk is 186 × 10⁴ CFU/ml.
b) The limit of the bacterial concentration in the pasteurized milk is 20000 CFU/ml, however, it can be seen that the sample of the milk possess more concentration of bacteria than the desired value. Therefore, the milk is not safe to drink by Public Health Standards.
