The product of 10 and the difference of a number x and 14 is 90

Julia went into a movie theater and bought 2 bags of popcorn and 5 pretzels, costing

Answer:

A bag of pop corn costs $8, and each Pretzel costs $4.25.

Step-by-step explanation:

Let $b$ be the price of popcorn, and $p$ the price of Pretzels. If the girl bought 2 bags of popcorn and 5 Pretzels and it cost her $37.25, we have the equation

$2b+5p=37.25$ <em>(this says that the cost of 2 popcorn bags plus 5 pretzels equals $37.25)</em> .

And, since Zoe bought 8 popcorn bags and 9 Pretzels with a total price of $102.25, we get the equation

$8b+9p=102.25$ <em> (this says that the cost of 8 popcorn bags plus 9 Pretzels equals $102.25).</em>

Thus, we have two equations

1. $2b+5p=37.25$

2. $8b+9p=102.25$

and we solve them by first multiplying equation (1) by 4:

$4(2b+5p=37.25 )\rightarrow (8b+20p=149)$ ,

and then subtracting it from equation (2):

$\:\:\:\:\: 8b+9p=102.25\\-(8b+20p=149)\\\line(1,0){3 cm}\\-11p=-46.75\\\\\boxed{p=\$4.25}$

Now we put this value of $p$ into equation (1) and get:

$2b+5(4.25)=37.25$

and we solve for $b$ to get:

$2b=37.25-21.5$

$\boxed{ b=8}$

Therefore, a bag of popcorn costs $8, and each Pretzel costs $4.25.

8 0

2 years ago

A 2001 study asked 1,924 male and 3,666 female undergraduate college students their favorite color. A 95% confidence interval fo

Mashcka [7]

The answer is false

5 0

2 years ago

The letters of the word mississippi are placed in a hat. what is the probability that the first two letters drawn are both i if

allochka39001 [22]

For the first letter drawn, there are no conditions/restrictions we need to consider. So, the number of ways to draw an i is:
$\text{Draw(i): } \frac{4}{11}$

For the second draw, the i is not replaced. That means, we've shrunk the sample space because we're dealing with less elements for the second draw. Firstly, one i disappears since we picked an "i" and there are 10 elements left, not 11.

Thus, to draw the second i, we have:
$\text{Draw(ii): } \frac{3}{10}$

$\text{P(drawing 2 i's): } \frac{4}{11} \cdot \frac{3}{10} = \frac{12}{110} = \frac{6}{55}$

3 0

2 years ago

A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Three marbles are randomly

Gnoma [55]

Answer: Last Option is correct.

Step-by-step explanation:

Since we have given that

Number of yellow marbles = 8

Number of green marbles = 9

Number of purple marbles = 3

Number of red marbles = 5

So,

Probability that there is atmost one purple marble is given by

$P(X=0)+P(X=1)\\\\=\frac{^{22}C_3}{^25C_3}+\frac{^3C_1\times ^{22}C_2}{^25C_3}\\\\=\frac{22\times 21\times 20}{25\times 24\times 23}+3\times \frac{22\times 21}{25\times 24\times 23}\\\\=0.971$

Hence, Last Option is correct.

3 0

2 years ago

Read 2 more answers

Bartolo is running a race. He determines that if he runs at an average speed of 15 feet/second, he can finish the race in 6 seco

Gelneren [198K]

Answer:

C

Step-by-step explanation:

the distance is 15•6 = 18•5 = 90 feet

so, time needed = 90/30 = 3 second

7 0

2 years ago