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ivanzaharov [21]
2 years ago
13

The equation of line l is -3y+4x=9. Write the equation of a line that is parallel to line l and passes through the point (-12,6)

Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line I is

-3y + 4x = 9

3y = 4x - 9

y = 4x/3 - 3

Comparing with the slope intercept form, slope = 4/3

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line passing through (- 12, 6) is - 3/4

To determine the y intercept, we would substitute m = - 3/4, x = - 12 and y = 6 into y = mx + c. It becomes

6 = - 3/4 × - 12 + c

6 = 9 + c

c = 6 - 9

c = - 3

The equation becomes

y = -3x/4 - 3

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we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

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M2/n2 is equivalent to _____.
tankabanditka [31]

Answer:

\frac{m^2}{n^2} is equivalent to m^2 \cdot n^{-2}

Step-by-step explanation:

Using exponent rules:

a^{-n}=\frac{1}{a^n}

Given the expression:

\frac{m^2}{n^2}

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Apply the exponent rule, we have;

m^2 \cdot n^{-2}

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Answer:

a) density of the object is 3995.01, b) the weight scale reads 22N c) the sum individually will be the same with when added together.

Step-by-step explanation:

The weight of the object in air is 8N,

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8/9.81 = 0.815,

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