Question

Petra records the score in each test she takes.

Answer 1

Answer:

$x-n+1$

Step-by-step explanation:

Given the mean of $n$ terms as $x$, and of $n-1$ as $x+1$:

We know that  $\bar X=\frac{1}{n}\sum x_i$ for $n$ terms.

Therefore $\sum x_n=n \bar X$ for $n$ terms;

For $n-1$  terms; $\sum x_n_-_1=(n-1)(x+1)=nx-x+n-1$

To find the nth score, we subtract the sum of (n-1) terms from the sum of n terms:

$n^t^h$ term=

$nx-(nx-x+n-1)\\=x-n+1$