Answer:
c. Not significant at .055
Step-by-step explanation:
When a pair of dice is rolled, we have 6²=36 possible outcomes. Only 2 of these outcomes have a total score of 11:
- When the first dice is 5 and the second is 6.
- When the first dice is 6 and the second is 5.
Then, we can calculate the probability of getting 11 as the quotient between the successs outcomes and the total outcomes.
Then, the probability of getting 11 is:

This probability is not equal or less than 0.05, so it is not significant at 0.055.
Answer:
I) 32.5
ii) 100.1
Step-by-step explanation:
I) 1056.25 = √1056.25
= 32.5
ii) 10020.01= √10020.01
=100.1
I say it is C. Basically I just eliminate the potential answered down. A could not be the one since not all student in 2nd period got 100% and average students got below 95%. B cannot be it since both box plot have the same median. I do not think D is it because of how the answer is told. "The 4th period class should get the reward. Their lowest score is an outlier, and should be thrown out," it sound childish and makeing a joke to put "and should be thrown out." I may be wrong but that is my opinion. The relatively the best and reasonable answer is C.
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Answer:
Correct option: third one -> 11.5 m3
Step-by-step explanation:
To find the volume of the ramp, first we need to find the volume of the rectangular prism and the volume of the triangular prism:
V_rectangular = 4m * 2m * 1m = 8 m3
V_triangular = (2m * 3.5m * 1m) / 2 = 3.5 m3
Now, to find the volume of the ramp, we just need to sum both volumes:
V_total = V_rectangular + V_triangular = 8 + 3.5 = 11.5 m3
Correct option: third one.
Answer:
BD = 4.99 units
Step-by-step explanation:
Consider the triangle ABD only.
The angle formed is 31 degrees which occurs between two sides that are AD and BC.
We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.
Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD
Using formula for tanθ
tanθ = Perpendicular/Base
tan31 = 3/BD
0.601 = 3/BD
BD = 3/0.601
BD = 4.99 units