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Zigmanuir [339]

2 years ago

4

Jason and Jessica spin a penny 80 times and record the results in this table. Heads up 12 tails up 68 .the relative frequency of

heads up is ______ .the relative frequency of landing tails up is ______.the two outcomes ______be considered equally likely.

2 answers:

seropon [69]2 years ago

7 0

Answer:

frequency for heads up: 0.15

frequency for tails up: 0.85

cannot

Step-by-step explanation:

relative frequency formula is $\frac{class frequency}{total}$

The total of the sample is 80. The class frequency for heads up = 12 , and tails up is 68

So, frequency for heads up is $\frac{12}{80}$ = 0.15

frequency for tails up is $\frac{68}{80}$ = 0.85

Since the probability outcomes between heads up and tails up is far, so the outcomes cannot be considered equally likely

Arlecino [84]2 years ago

6 0

Answer:

frequency for heads up: 0.15

frequency for tails up: 0.85

cannot

Step-by-step explanation:

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A gym offers three levels of membership based on the number of visits per month, as represented by the table. Kaleigh wants to k

Otrada [13]

Answer:

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Step-by-step explanation:

Let

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2) For the interval of x equal to ---->(12,16] (open circle at left and close circle at right)

The domain is all whole numbers greater than 12 visits and less than or equal to 16 visits

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For x=12 ----> y=4(12)+32=$80

For x=16 ----> y=4(16)+32=$96

The range is the interval ----> (80,96] (open circle at left and close circle at right)

All real numbers greater than $80 and less than or equal to $96

3) For the interval of x equal to ---->(16,24] (open circle at left and close circle at right)

The domain is all whole numbers greater than 16 visits and less than or equal to 24 visits

The value of y is

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Step-by-step explanation:

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2 years ago

-4 + -7 (-2) =? Minus equations always give me trouble :/

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<span>-4 + -7 (-2)
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Read 2 more answers

A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the number

serg [7]

Answer:

The probability distribution is

X : 0 1 2

f(X) : 2/7 4/7 1/7

Step-by-step explanation:

Let x is the number of defective sets purchased by the hotel.

Total number of television sets = 7

Total number of defective television sets = 2

Since there are 2 defective television sets and hotel purchase 3 sets, So, X=0,1,2.

If X=0,

$P(X=0)=\frac{^5C_3}{^7C_3}=\frac{10}{35}=\frac{2}{7}$

If X=1,

$P(X=1)=\frac{^5C_2\cdot ^2C_1}{^7C_3}=\frac{10\cdot 2}{35}=\frac{4}{7}$

If X=2,

$P(X=2)=\frac{^5C_1\cdot ^2C_2}{^7C_3}=\frac{5\cdot 1}{35}=\frac{1}{7}$

The probability distribution is

X : 0 1 2

f(X) : 2/7 4/7 1/7

The probability histogram is shown below.

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