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tankabanditka [31]
2 years ago
12

A cubic box is completely filled with 2,179 g of water. What is the length of one side of the box, in meters? m Explain your rea

soning. Since the density of water is g/cm3, then the volume of 2,179 g of water is cm3. A cubic box with a volume of cm3 is cm on each side. Converting cm to meters, the cube is m on each side.
Mathematics
1 answer:
lisov135 [29]2 years ago
6 0

Answer:

l\approx 1.296\,cm

Step-by-step explanation:

The water density is approximately 1 gram per cubic centimeter, which means that 1 gram of water occupies a volume of a cubic centimeter. Hence, 2.179 grams occupies a volume of 2.179 cubic centimeters.

Let assume volume occupied by the water has a cube-like shape, whose side has the following measure:

l = \sqrt[3]{2.179\,m^{3}}

l\approx 1.296\,cm

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A radar gun measured the speed of a baseball at 103 miles per hour. If the baseball was actually going 102.8 miles per hour, wha
zimovet [89]

Answer:

.998%

Step-by-step explanation:

102.8/103 = .9980582524

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2 years ago
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Match the line segments with their lengths. If necessary, round your answers to the nearest hundredth. PLEASE HELP ME
Stella [2.4K]

Answer:

the fourth one

Step-by-step explanation:

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2 years ago
If the legs of an isosceles right triangle have a length of 15 StartRoot 2 EndRoot ft, what is the length of the hypotenuse? 7.5
Likurg_2 [28]

Answer:

The length of the hypotenuse is 30 feet

Step-by-step explanation:

Here, we are to calculate the length of the hypotenuse of an iscosceles right triangle.

For the triangle to be isosceles, it means that the opposite and the adjacent are equal in length.

Now, to calculate the value of the hypotenuse, we make use of the Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Mathematically;

let’s say the hypotenuse is length h feet

h^2 = {15√(2)}^2 + {15√(2)}^2

h^2 = (225 * 2) + (225 * 2)

h^2 = 450 + 450

h^2 = 900

h = √(900)

h = 30 feet

4 0
2 years ago
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Drag each expression to show whether it is equivalent to
Kazeer [188]

Answer:

We need to find which expressions are equivalent to 6(c+6), 6c+6 or neither.

6c+12: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

6c+12=+(c+2)

Therefore, this expression is equivalent to neither of the given expressions.

2(3c+3): We just need to apply the distributive property.

2(3c+3)=6c+6

Therefore, this expression is equivalen to 6c+6.

We use the same process to the other expressions.

(6c)+(6\times 6)=6c+36=6(c+6)

3c+6+3c=6c+6

6c+36=6(c+6)

(6+c)+(6+6)=c+18, equivalent to neither.

7 0
2 years ago
Alice and Briana each participate in a 5 kilometer race. Alice's distance covered, in kilometers, after t minutes can be modeled
Pavel [41]

Answer:

a. Alice

b. Briana

c. 0.51 minutes

Step-by-step explanation:

a. Alice formula is valid for any t > 0 minutes, but Briana formula is only valid for

2t - 1 > 0

2t > 1

t > 1/2 minutes

b. They finish when their covered distance is equal to 5 kilometers. For Alice:

t/4 = 5

t = 5*4 = 20 minutes

For Briana:

√(2t - 1) = 5

2t - 1 = 5²

2t = 25 + 1

t = 26/2

t = 13 minutes

c. They are side by side when they have covered the same distance, that is:

t/4 = √(2t - 1)

(t/4)² = 2t - 1

t²/16 = 2t - 1

t² = 16*(2t - 1)

t² = 32t - 16

t² - 32t + 16 = 0

Using quadratic formula:

t = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

t = \frac{32 \pm \sqrt{-32^2 - 4(1)(16)}}{2(1)}

t = \frac{32 \pm 30.98}{2}

t_1 = \frac{32 + 30.98}{2}

t_1 = 31.49

t_2 = \frac{32 - 30.98}{2}

t_2 = 0.51

Only the second answer has sense for this problem because the race already finished before they spent 31.49 minutes in it.

4 0
2 years ago
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