To expand (3 - 2x)^6 use the binomial theorem:
(x + y)^ n = C(n,0) x^ny^0 + C(n,1)x^(n-1) y + C(n,2)x^(n-2) y^2 + ...+ C(n,n+1)xy^(n-1) + C(n,n)x^0y^n
So, for x = 3, y = -2x , and n = 6 you get:
(3 - 2x) ^6 = C(6,0)(3)^6 + C(6,1)(3)^5 (-2x) + C(6,2) (3)^4 (-2x)^3 + C(6,3) (3^3) (-2x)^4 + C(6,4)(3)^2 (-2x)^4 + C(6,5) (3) (-2x)^5 + C(6,6) (-2x)^6
So, the sixth term is C(6,5)(3)(-2x)^5 = 6! / [5! (6-5)! ] * 3 * (-2)^5 x^5 = - 6*3*32 = - 576 x^5.
The coefficient of that term is - 576.
Answer: - 576
Answer:
The dimensions that minimize the amount of cardboard used is
x = 31 cm , y = 34 cm & Z = 15.54 cm
Step-by-step explanation:
Volume of the cardboard = 16,384 
The function that represents the area of the cardboard without a lid is given by
------ (1)
Volume of the cardboard with sides x, y & z is


Put this value of z in equation (1) we get


Differentiate above equation with respect to x & y we get


Take 

------ (2)
------- (3)
By solving equation (2) & (3) we get

x = 31 cm
From equation 2

y = 32768 (
)
y = 34 cm


Z = 15.54 cm
Thus the dimensions that minimize the amount of cardboard used is
x = 31 cm , y = 34 cm & Z = 15.54 cm
Answer:
<h2>The equation is

.</h2>
Step-by-step explanation:
The equation of a hyperbola is represented by
, where (h, k) is the center of the hyperbola.
As per the given condition, h = -2 and k = 4.
Thus, the equation becomes
.
One vertex is (-2, 7).
Hence, putting x = -2 and y = 7, we get
.
The slope of the asymptote is
.
Hence,
.
Thus, the equation is
.
Answer:
2
Step-by-step explanation:
Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2
Substituting π/2 into the function
lim x-->π/2 sin(x)-1/cos 2(x)
= sin(π/2) - 1/cos(2)(π/2)
= 1 - 1/cosπ
= 1- 1/-1
= 1 -(-1)
= 1+1
= 2
Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2
The answer to your question is A