There are many examples you can choose from, but one great example, a venus fly trap, and a lotus, for example. The two examples given differ because they:
*provide themselves with different types of foods
*have a different system of reproducing, as well as growing
*and live in two different types of environments.
Also, remember, the fly trap is a carnivorous plant, while the lotus is not
Answer: Option B.
Precise but inaccurate.
Explanation:
It is precise because the measurement taken with well incremated tool reflect how close it is to the actual value i.e it has the quality of been exact but diet to the missing of 4.0 centimeter because a hungry beaver made a snack of it earlier that day the measurements will be INACCURATE because it does not conform with the result of the standard or correct value to be gotten.
Molecular Biology
This field of study deals with everything related to macromolecules, thus, what you will need for molecular biology would be something you could get proteins and nucleic acids from. Among the choices, the DNA of a pig and a calf would be the most helpful.
Comparative Anatomy
Comparative anatomy is a field of study that focuses on any similarities or differences between the anatomy or structure of different animals or species in general. Among the options, having the limb structure of a pig and a calf would allow you to practice the field since you have a structure to compare.
Developmental Biology
In this field, your concern would be how species grow and develop. For you to properly observe the growth and development, you must have the embryo of a pig and a calf. Therefore, among the options, this is the correct piece of evidence for this field.
IN SUMMARY:
Molecular Biology - Both DNA of a pig and a calf
Comparative Anatomy - Both limb structure of a pig and a calf
Developmental Biology - Embryo of a pig and a calf
So let’s substitute that into the
third equation and solve for B. B = H + T B = 9 + (9 + 1/2B) B = 18 + 1/2B Then
subtract 1/2B from both sides: 1/2B = 18 Multiply both sides by two: B = 36 Now
we know the value of B and the value of H. Substitute this back into the second
equation and solve for T. T = H + 1/2B T = 9 + (1/2)36 T = 9 + 18 = 27 Step 4:
Plug all values of H, T, and B into the final equation. Total length of fish =
H + T + B Total length of fish = 9 +27 + 36 = 72.