This is<span> not the exact, precise </span>definition<span> of a </span>limit. If you would like to see the more precise and mathematical definition<span> of a </span>limit<span> you should check out the The </span>Definition<span> of a </span>Limit<span> section at the end of this chapter. The </span>definition<span> given above </span>is<span> more of a “working” </span>definition<span>.</span>
Answer:
The value of y is 6
units ⇒ 2nd answer
Step-by-step explanation:
In the attached figure
∵ ∠MTN is a right angle
∵ TU is the altitude of the triangle
- There are some rules in this triangle let us revise them
- (NT)² = NU . NM
- (MT)² = MU . MN
- (TU)² = MU . NU
- TM . TN = TU . MN
∵ NU = 9 units
∵ UM = 3 units
∵ MN = UM + NU
∴ MN = 3 + 9 = 12 units
- By using the 1st rule above
∴ (NT)² = 9 × 12
∴ (NT)² = 108
- Take a square root to both sides
∴ NT =
- Simplify the root
∴ NT = 6
units
∵ NT is y
∴ y = 6
units
The value of y is 6
units
The answer will be D. 7/10 because you have 10 numbers and you want to have a number greater than 3 so it would be 10-3=7 and 7 would go over 10 because there are 7 numbers greater than 3 but less than 10.
Answer:
x = 9
Step-by-step explanation:
The trick here is knowing that JKM and MKL are equal, which means MKL is equal to JKL/2. From that knowledge, we can solve.
MKL = JKL/2
5x + 1 = 46
5x = 45
x = 9
The answer would be C because 24-3=21 then you would do 21/1.50=14