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Korvikt [17]
2 years ago
8

Erika is writing a coordinate proof to show that the diagonals of a rectangle are congruent. She begins by assigning coordinates

to the vertices of a rectangle as shown.
Which sentence describes what Erika should do to prove that the diagonals of the rectangle are congruent?

Show that the slope of KM¯¯¯¯¯¯¯ is ba and the slope of JL¯¯¯¯¯ is −ba.
Show that the diagonals intersect at (a2, b2) .
Show that JL=KM=a2+b2−−−−−−√.
Show that JL¯¯¯¯¯ and KM¯¯¯¯¯¯¯ have the same midpoint.

Mathematics
2 answers:
klemol [59]2 years ago
7 0

Answer:

Option C is the correct choice.

Step-by-step explanation:

We are given the coordinates of rectangle and we are asked to find the correct option that describes that diagonals JL and KM are congruent.

Since we that a rectangle have four right angles.

We will use Pythagorean theorem to prove that diagonals JL and KM are congruent.

In triangle KLM we can see that KL is b units long and LM is a units long. By Pythagorean theorem \sqrt(a^{2}+b^{2})=KM

In triangle JML we can see that JM is b units long and LM is a units long. By Pythagorean theorem \sqrt(a^{2}+b^{2})=JL

Therefore, we can see that \sqrt(a^{2}+b^{2})=KM=LM and option C is the correct choice.  

Solnce55 [7]2 years ago
3 0
I think its the last one, not to sure but I hope it helps. sorry if its wrong.
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Two well-known aviation training schools are being compared using random samples of their graduates. It is found that 70 of 140
egoroff_w [7]

Answer:

Step-by-step explanation:

Given that two well-known aviation training schools are being compared using random samples of their graduates

Fly more academy 70 of 140

Blue Yonder   104 of 260

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a) Pooled proportion=\frac{174}{400} \\=0.435

b) H0: p1 = p2

Ha: p1 ≠p2

(two tailed test)

p difference= \frac{70}{140} -\frac{104}{260} =0.10

std error for difference (using pooled proportion) = \sqrt{\frac{0.435*0.565}{400} } \\=0.0248

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Since p < 0.05 our significant level we reject H0

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8 0
2 years ago
A motorcycle and a car leave an intersection at the same time. the motorcycle heads north at an average speed of 20 miles per​ h
satela [25.4K]
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\boxed{d=v \times t}
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The car
d = 48 × t
d = 48t

The motorcycle
d = 20 × t
d = 20t

At the end of t hours, the car is 48t miles (east) from the start point and the motorcycle is 20t miles (north) from the start point.

Second, determine the distance between 48t miles at east and 20t miles at north using pythagoras
distance = \sqrt{(48t)^{2}+(20t)^{2}}
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distance = \sqrt{2704t^{2}}
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The expression for their distance apart at the end of t hours is 52t
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What you must do in this case is to use the potential type function given in the problem:
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