Answer: 58 ft × 58 ft
Step-by-step explanation:
Let the length of the region = x feet
And, the width of the region = y feet
Since, the perimeter of the region = 234 feet ( Given )
⇒ 
⇒ 
⇒ 
Again the area of the region, A = xy
⇒ 
⇒
By differentiating the above equation with respect to x,
⇒
For maxima or minima,




Again differentiating equation A'(x) with respect to x,
We get, A''(x) = -2
Hence, For x = 58.5 A''(x) = negative
⇒ For x = 58.5 feet the area A(x) is maximum,
⇒ The length of the region having maximum area = x = 58.5 feet
And, the width of the region having maximum area = y = 117-x= 117 - 58.5=58.5 feet,
⇒ The dimension of the region having the maximum area = 58.5 ft × 58.5 ft
Answer:
12x - 15 dollars
Step-by-step explanation:
Sunny earns $12 per hour for delivering cakes.
She worked for x hours this week.
Unfortunately, she was charged $15 for a late delivery on Tuesday
She was supposed to earn $12 × x = $12x this week
But she was charged $15 for late delivery on Tuesday
So her net earning this week is; $12x - $15
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :

Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
![\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B365%7D%7B365%7D%5Ctimes%20%5Cfrac%7B364%7D%7B365%7D%5D)
![\text{P(2 born on same day) }=1-[\frac{364}{365}]](https://tex.z-dn.net/?f=%5Ctext%7BP%282%20born%20on%20same%20day%29%20%7D%3D1-%5B%5Cfrac%7B364%7D%7B365%7D%5D)

The probability that among ten students in a class, at least two of them share a birthday is 0.002.