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allsm [11]
2 years ago
12

Could 7.7 cm , 4.0 cm , 7.7 cm,4.0 cm,7, point, 7, start text, space, c, m, end text, comma, 4, point, 0, start text, space, c,

m, end text, comma and 1.7 cm 1.7 cm1, point, 7, start text, space, c, m, end text be the side lengths of a triangle?
Mathematics
2 answers:
Lyrx [107]2 years ago
8 0

Answer:

With given side lengths a triangle <u>could not</u> be created.

Step-by-step explanation:

Given:

First side length = 7.7 cm

Second side length = 4.0 cm

Third side length = 1.7 cm

We need find whether this could be the side length of the triangle.

Solution:

Now we know that;

By Triangle In equality property which states that;

"Sum of the two side length of the triangle must be greater than third side."

It should fulfill all three conditions;

So we will find the same.

Condition 1:

First Side + Second Side > Third side

7.7+4.0>1.7\\\\11.7>1.7

Hence This condition is true.

Condition 2:

Second side + Third Side > First side

4.0+1.7>7.7\\\\5.7>7.7

Hence This condition is False.

Condition 3:

First side + Third Side > Second side

7.7+1.7>4.0\\\\9.4>4.0

Hence This condition is true.

Since One of the condition is false hence With given side lengths a triangle could not be created.

hichkok12 [17]2 years ago
8 0

Answer: It was no

Step-by-step explanation: Khan

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Aleksandr [31]
Given that t<span>he x-axis represented the number of small tanks and the y-axis represented the number of large tanks.

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2 years ago
One of the factors of the polynomial x3 − 5x2 is x + 3. What is the other factor?
blondinia [14]

Answer:

C. x² − 8x + 24 − 72/(x+3)

Step-by-step explanation:

See attached picture for long division method.

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A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random
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Answer with explanation:

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Standard deviation : \sigma=\text{ 3.1 pounds.}

Sample size : n = 36

Claim : \mu\neq50

∴ H_0:\mu=50

H_1:\mu\neq50

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By using a z statistic and a 0.05 level of significance. Reject  H_0 if z < -1.960 or is z> 1.960.

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LESSON 1 SESSION 1
denpristay [2]

Answer:

  • <em>Between which two tens does it fall?</em><em> </em><u>Between 25 and 26 tens</u>

<em><u /></em>

  • <em>Between which two hundreds does it fall?</em> <u>Between 2 and 3 hundreds</u>

Explanation:

The place-value chart is:

Hundreds         Tens      Ones

       2                   5             3

<em><u /></em>

<em><u>a)  Between which two tens does it fall? </u></em>

Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.

From that you can write:

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<u><em>b) Between which two hundreds does it fall?</em></u>

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Conclusion: 253 is between 2 hundreds and 3 hundreds.

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