The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units. Write an equation to determine the length (l
1 answer:
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Answer:
16 cm
Step-by-step explanation:
Let the three consecutive even integers representing the sides of the triangle PQR be x, (x +2) and (x + 4).
Since, perimeter of triangle PQR = 42 cm
Answer:
Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))
1. R is reflexive if for each element a∈B, aRa.
2. R is symmetric if satisfies that if aRb then bRa.
3. R is transitive if satisfies that if aRb and bRc then aRc.
Then, our set B is .
a) We need to find a relation R reflexive and transitive that contain the relation
Then, we need:
1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,
2. Observe that
- 1R4 and 4R1, then 1 must be related with itself.
- 4R1 and 1R4, then 4 must be related with itself.
- 4R1 and 1R2, then 4 must be related with 2.
Therefore is the smallest relation containing the relation R1.
b) We need a new relation symmetric and transitive, then
- since 1R2, then 2 must be related with 1.
- since 1R4, 4 must be related with 1.
and the analysis for be transitive is the same that we did in a).
Observe that
- 1R2 and 2R1, then 1 must be related with itself.
- 4R1 and 1R4, then 4 must be related with itself.
- 2R1 and 1R4, then 2 must be related with 4.
- 4R1 and 1R2, then 4 must be related with 2.
- 2R4 and 4R2, then 2 must be related with itself
Therefore, the smallest relation containing R1 that is symmetric and transitive is
c) We need a new relation reflexive, symmetric and transitive containing R1.
For be reflexive
- 1 must be related with 1,
- 2 must be related with 2,
- 3 must be related with 3,
- 4 must be related with 4
For be symmetric
- since 1R2, 2 must be related with 1,
- since 1R4, 4 must be related with 1.
For be transitive
- Since 4R1 and 1R2, 4 must be related with 2,
- since 2R1 and 1R4, 2 must be related with 4.
Then, the smallest relation reflexive, symmetric and transitive containing R1 is
<h2>Answer:</h2><h2>volume of the cylinder = 2π
</h2>
Step-by-step explanation:
The height of a cylinder is twice the radius of its base.
Let the height of the cylinder = 2x
Let the radius of the cylinder = x
By formula, volume of the cylinder = π h
here r = x, h = 2x
substituting the values in the equation, we get
volume of the cylinder = π h = π
(2x)
volume of the cylinder = 2π
Answer:
y = 0.2x + 250
Step-by-step explanation:
let the sales be x and y be earnings
thus,
given
x₁ = $3,500 ; y₁ = $950
and,
x₂ = $2,800 ; y₂ = $810
Now,
the standard line equation is given as:
y = mx + c
here,
m is the slope
c is the constant
also,
m =
or
m =
or
m = 0.2
substituting the value of 'm' in the equation, we get
y = 0.2x + c
now,
substituting the x₁ = $3,500 and y₁ = $950 in the above equation, we get
$950 = 0.2 × $3,500 + c
or
$950 = $700 + c
or
c = $250
hence,
The equation comes out as:
y = 0.2x + 250