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allochka39001 [22]
2 years ago
14

The perimeter of a rectangle is 343434 units. Its width is 6.56.56, point, 5 units. Write an equation to determine the length (l

)(l)(, l, )of the rectangle. Find the length of the rectangle.
Mathematics
1 answer:
stiv31 [10]2 years ago
5 0

Answer:

Step-by-step explanation:

perimiter=2(Length+Width)

P=2(L+W)

solve for L

distribute

P=2L+2W

minus 2W

P-2W=2L

divide by 2

\frac{P-2W}{2}=L

given that P=34 units and W=6.5 units

\frac{34-2(6.5)}{2}=L

the equation would be L=p2w/2 or L= p/2=w

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Mr. Abraham is 36 years old. His wife is 6 years younger than him and their son is 24 years old younger than his wife. What is t
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Hi!
We know that Mr. Abraham’s wife is 6 years younger than him, which is 36-6, which means his wife is 30 years old.

We also know that Mr A’s son is 24 years younger than his wife, which is 30-24, which is 6.

As of right now, we now know that:
Mr. A is 36
Mr. A’s wife is 30
Mr. A’s son is 6

It’s asking for the ratio of Him:Wife:Son, so 36:30:6.

BUT, it’s asking for simplest form, so divide each of those numbers by 6.

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8 0
2 years ago
14.75x - 2.3 = 5.25x + 45.2
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14.75x - 23=5.25x+45.2
14.75x-23-5.25x=5.25x+45.2-5.25x
14.75-5.25x=9.5
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9.5x-23+23=45.2+23
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2 years ago
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Markus scored 85, 92, 82, and 94 on the first four tests of the semester. His teacher has not yet told him his score on his fift
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A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the
Ksivusya [100]

Answer:

P(X = 0) = 0.42

P(X = 1) = 0.46

P(X = 2) = 0.12

Step-by-step explanation:

We have these following probabilities:

40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.

30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.

Probability mass function

Probability of each outcome(0, 1 and 2 files corrupted).

No files corrupted:

60% probability that the first file is not corrupted.

70% probability that the second file is not corrupted.

So

P(X = 0) = 0.6*0.7 = 0.42

One file corrupted:

First one corrupted, second no.

40% probability that the first file is corrupted.

70% probability that the second file is not corrupted.

First one ok, second one corrupted.

60% probability that the first file is not corrupted.

30% probability that the second file is corrupted.

P(X = 1) = 0.4*0.7 + 0.6*0.3 = 0.46

Two files corrupted:

40% probability that the first file is corrupted.

30% probability that the second file is corrupted.

P(X = 2) = 0.4*0.3 = 0.12

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2 years ago
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