Disagree.
b/8 = 56; multiply both sides by 8 to solve for b, and you get b = 448
Let us take number of $5 bills = x and
number of $10 bills = y.
Give that "number of $10 bills is twice the number of $5 bills".
So, y is twice of x,
We can setup an equation.
y= 2x ............................... equation(1)
Total value of all bills = $125.
We can setup another equation,
5*(number of $5 bills) + 10*(number of $10 bills) =125.
5(x) +10(y) = 125 ................................... equation(2)
Plugging y=2x in equation(2), we get
5(x) +10(2x) = 125 .
5x+20x = 125.
Adding like terms
25x = 125
Dividing both sides by 25.
25x /25 = 125/25
x= 5.
Plugging x=5 in first equation, we get
y= 2(5) = 10.
Therefore, number of number of $5 bills=5 bills and number of $10 bills = 10 bills.
Answer:
12.05$
Step-by-step explanation: 2.65$ x 3 - 20$= 12.05$
Answer:
300
Step-by-step explanation:
Sum the parts of the ratio : 3 + 2 = 5 parts
Divide the number of appointments by 5 to find the value of one part of the ratio, that is
= 100 ← value of 1 part of the ratio
The mums consisted of 3 parts, hence
3 × 100 = 300 ← appointments with mums
Let a the price of a basket of oranges be O, that of a basket of apples A, a basket of mangoes M and a basket of peaches P, then
O + A + M + P = 790 . . . (1)
M - 4 = P + 7 = 3O = A/2 . . . (2)
From (2), we have:
M = P + 11
O = (P + 7)/3
A = 2P + 14
Substituting for M, O and A into (1), gives:
(P + 7)/3 + 2P + 14 + P + 11 + P = 790
P + 7 + 6P + 42 + 3P + 33 + 3P = 2370
13P + 82 = 2370
13P = 2288
P = 176
Therefore, the price of a basket of peaches is Rs176.