Question

An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. What is the maximum possible lenght of the pencil?

Answer 1

the maximum possible length of the pencil is 13 inches

Step-by-step explanation:

Here we have , An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. We need to find What is the maximum possible length of the pencil . Let's find out:

We know that maximum length which can be fitted in envelope will be the length of diagonal of envelope . So

By Pythagoras theorem

$Diagonal^2 = length^2 +breadth^2$

⇒ $Diagonal^2 = length^2 +breadth^2$

⇒ $Diagonal^2 =5^2 +12^2$

⇒ $Diagonal^2 =25 +144$

⇒ $Diagonal^2 = 169$

⇒ $\sqrt{Diagonal^2} = \sqrt{169}$

⇒ $Diagonal= 13 inch$

Therefore,  the maximum possible length of the pencil is 13 inches .