he polynomial 2x3 − 5x2 + 4x − 10 is split into two groups, 2x3 + 4x and −5x2 − 10. The GCFs of each group is then factored out.
2 answers:
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A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
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For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
</span>
For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.
Given :
Liam has a bag of b beads.
He gives 20 beads to his sister.
He then makes 4 necklaces with the same of beads on each necklace using all of the remaining beads.
To Find :
Write an expression that represents the number of beads on each necklace.
Solution :
Number of necklace remains after giving 20 beads to his sister is ( b - 20 ).
Number of beads on each necklace using all of the remaining beads is :
Hence, this is the required solution.