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melomori [17]
1 year ago
8

What is the answer for this question (What does the equation 100+0.05p=0.25p represent?)

Mathematics
1 answer:
spin [16.1K]1 year ago
7 0

Answer:

100+0.30p

hope this helps

have a good day :)

Step-by-step explanation:

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Please I need help ASAP The answer choices $1,300 .  $1,500  .  $3,300 .   $4,300 .   $4800/1 copier .   -$500/1 year .   V(x) =
Dafna11 [192]

1. The function that models this equation is:

Since the value V (x) of the copier depreciates over time, hence the 500 must be negative, therefore the equation:

V(x) = −500x + 4800

 

2. The rate of change for the function is:

The rate of change is also equivalent to the slope of the equation, in this case the slope is equal to:

-$500/1 year

 

3. The model predicts that the value of the copier after 3 years will be:

Substituting the value of x = 3 to the function gives us:

V(x) = −500 (3) + 4800

V(x) = $3,300

 

4. The model predicts that the value of the copier after 7 years will be:

Substituting the value of x = 7 to the function gives us:

V(x) = −500 (7) + 4800

V(x) = $1,300

3 0
2 years ago
Read 2 more answers
The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

P'(t) = $3 per day RATE OF CHANGE  

the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

P(t) = 20 + 12 sin 15π/30 − 6 sin 15π/15 + 4 sin 15π/10 − 3 sin 30πt/15  

P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

P(t) = 20 + 12(1) − 6(0) + 4(-1) − 3(0) = 20 + 12 - 0 - 4 - 0 = 20 + 12 - 4  

P(t) = $28 per share close price



4 0
2 years ago
The cost of tuition at Cornell University is 43,000 per year when rounded to the nearest thousand what is the greatest possible
melomori [17]
The cost of the tuitions will if you round off 43:000 it would $43
3 0
2 years ago
a shopkeeper sold goods for rs 2400 and made a profit of 25% in the process. find his profit per cent if he had sold his goods f
miv72 [106K]

case 1,

Let the CP be ₹x,

SP = ₹2400

Profit = SP – CP

= 2400 – x

Profit % = {(2400–x)/ x} × 100%

According to the question,

{(2400–x)/ x} × 100 = 25

=> (2400–x)/ x= 25 /100

=> 100(2400–x) = 25x [ cross multiplication]

=> 240000 – 100x = 25x

=> 240000 = 25x + 100x

=> 240000 = 125x

=> 240000/125 = x

=> x = 1920

So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

= 2040 – 1920

= ₹120

profit % = 120/1920 × 100%

= 16%

<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>
6 0
2 years ago
There is a harvest festival each year on the planet Bozone. During that time, most of the Bozone residents sit down to rejoice a
Oliga [24]

Answer:

The price would be decreased by 18 bozats

Step-by-step explanation:

The following information is given in the question

x = number of kilograms of snig sold

P = Price per kilogram

And, the equation is

p = 300 - 18x

Now if an extra kilogram is sold so it should be x+1

Now the new price is

New price = 300 - 18(x + 1)

= 300 - 18x - 18

Therefore the price would be decreased by 18 bozats

8 0
2 years ago
Read 2 more answers
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