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devlian [24]
1 year ago
6

A fleet repair facility has the capacity to repair 800 trucks per month. However, due to scheduled maintenance of their equipmen

t, management feels that they can repair no more than 600 trucks per month. Last month, two of the employees were absent several days each, and only 400 trucks were repaired. What is the efficiency of the repair shop?
Business
1 answer:
Svetlanka [38]1 year ago
7 0

Answer:

Efficiency of the repair shop is 66.67%

Explanation:

Efficiency is the ability to avoid the available resources such as workforce, time, money, material etc. The maximum output in the available resources is efficiency.

Total Capacity of repair fleet = 800 trucks

Effective Capacity of repair fleet = 600 trucks

Actual Output = 400 trucks

Trucks Utilization = Actual Output / Total Capacity = (400 / 800) x 100 = 50%

Efficiency = Actual output / Effective Capacity = (400 / 600) x 100 = 66.7%

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When offered a choice between two sodas and 11 pizza slices or 14 sodas and three pizza slices, Nami replies that she would be e
dimaraw [331]

Answer:

Nami's indifferent in 3 points that lie on the different curve, the three poits

that are mentions are -

1. Point C - 5 soda and 6 pizza slices

2. Pont E - 2 soda and 11 pizza slices

3. Point F - 14 soda and 3 pizza slices.

Do check the graph,

In which x-axis is for pizza slices and Y-axis is for soda counts. The all three points are represented as E -( 2, 11), C - (5, 6), and F - ( 14, 3).

5 0
2 years ago
stock that has a current price of $25.00, a beta of 1.25, and a dividend yield of 6%. If the Treasury bill yield is 5% and the m
photoshop1234 [79]

Answer:

$30.2067

Explanation:

From the given question, using the dividend discount model

V_0 = \dfrac{D_1}{r - g}

where:

r is the Expected return on stock and be calculated as:

Expected return on stock = Risk free rate + Beta × (Expected Market Return - Risk free rate)

Expected return on stock = 5% + 1.25 × (14% - 5%) = 16.25%

However, the current price in this process will b used as the dividend price for all future expenses.

Dividend Yield = Current Dividend/The Share Price

Current dividend D0 = 6% × $25.00 = $1.50

D₁ = D₀ × (1 + g)

D₁ = 1.5 × (1 + g)

Thus, we can now employ the use of the growth dividend model (constant) to determine the value of g as follows:

25 = \dfrac{1.5 \times (1 + g)}{0.1625 - g}

By cross multiply, we have:

4.0625 - 25g = 1.5 + 1.5g

collect like terms, we have:

4.0625 - 1.5 = 1.5g + 25g

2.5625 = 26.5g

Divide both sides by 26.5, we have:

2.5625/26.5 = 26.5g/26.5

g = 9.67%

Similarly, suppose the value for the second year-end to be Y₂;

Then the constant growth dividend model can be computed as:

Y_2 = \dfrac{D_3}{r - g}

where;

D₃ = D₂ × (1 + g)

D₂ × (1 + g) = D₁ × (1 + g) × (1 + g)

D₁ × (1 + g) × (1 + g) = D₀ × (1 + g) × (1 + g) × (1 + g)

D₁ × (1 + g) × (1 + g) = D₀ × (1 + g) × (1 + g) × (1 + g)  = D₀ × (1 + g) × 3

D₃ = 1.5 × (1 + 9.67%) × 3

D₃ = $1.9876

Finally:

Y_2 = \dfrac{D_3}{r - g}

Y_2 = \dfrac{1.9876}{0.1625 - 0.0967}

Y₂ = $30.2067

7 0
1 year ago
Note: Use the Tax Tables to calculate the answers to the problems listed.
kkurt [141]

Answer:

  1. $104.50
  2. $67.50
  3. $65.50
  4. $77.50
  5. $56.50

Explanation:

the income tax to withhold from the biweekly wages are :

  • <u> </u><u>Karen Overton (single, 0 allowances), $900 wages</u>

=$34.90 + ($900 - 436) x 15%

= $104.50

  • <u> Nancy Haller (married, 4 allowances), $1,000 wages </u>

=($1000 - 325 ) x 10%

= $67.50

  • <u>Alan Glasgow (married, 1 allowance), $980 wages </u>

=($980 - 325 ) x 10%

= $65.50

  • <u>Joseph Kerr (single, 4 allowances), $720 wages </u>

= $34.90 + ($720 - $436) x 15%

= $77.50

  • <u> </u><u>Ginni Lorenz (single, 1 allowance), $580 wages</u>

= $34.90 + ($580 - $436) x 15%

= $56.50

5 0
2 years ago
Motorist has a flat tire and is in the process of changing it. one of the lug nuts is very tight and he is trying to remove it.
Lostsunrise [7]
<span>Actually motorist best approach here is to trying to figure out the correct removing rotation of lug nuts, then rotate in that direction it smoothly as possible by applying some oil or grease,which will surely do the need of the motorist to change the flat tire safely, instead of pushing or pulling it hard, which not solve the problem at all even after lot of time and energy,</span>
4 0
2 years ago
Each week a soft drink machine sells x cans of soda for $0.75/soda. The cost to the owner of the soda machine for each soda is $
Assoli18 [71]

Answer:

$34.8

Explanation:

Profits = sales - costs( variable costs +fixed costs)

In this case : total sales will be price $0.75 x units sold X= 0.75X

Variable costs : =$10 x units sold= $10x

Fixed cost remain $25 as they are not affected by quantity.

profits for the Week

P= (0.75x- 0.10x)-$25

Profit for the week with units sold as 92: x = 92

p= ( {0.75x92} - {0.10x92} )- $25

P= $69 - $9.2- $25

P=$59.8- $25

   =$34.8

3 0
2 years ago
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