Answer:
The code solution is written in Java.
- import java.util.Scanner;
-
- public class TestScore {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
-
- System.out.print("Please enter first score: ");
- double firstScore = input.nextDouble();
- System.out.println("Grade: " + determineGrade(firstScore));
-
- System.out.print("Please enter second score: ");
- double secondScore = input.nextDouble();
- System.out.println("Grade: " + determineGrade(secondScore));
-
- System.out.print("Please enter third score: ");
- double thirdScore = input.nextDouble();
- System.out.println("Grade: " + determineGrade(thirdScore));
-
- System.out.print("Please enter fourth score: ");
- double fourthScore = input.nextDouble();
- System.out.println("Grade: " + determineGrade(fourthScore));
-
- System.out.print("Please enter fifth score: ");
- double fifthScore = input.nextDouble();
- System.out.println("Grade: " + determineGrade(fifthScore));
-
- System.out.println("Average score: " + calcAverage(firstScore, secondScore, thirdScore, fourthScore, fifthScore));
-
- }
-
- public static double calcAverage(double score1, double score2, double score3, double score4, double score5){
- double average = (score1 + score2 + score3 + score4 + score5) / 5;
- return average;
- }
-
- public static String determineGrade(double score){
- if(score >= 90){
- return "A";
- }
- else if(score >= 80 ){
- return "B";
- }
- else if(score >=70){
- return "C";
- }
- else if(score >=60){
- return "D";
- }
- else{
- return "F";
- }
- }
- }
Explanation:
Firstly, create the method, <em>calcAverage()</em>, that takes five test scores. Within the method, calculate the average and return it as output. (Line 33 - 36)
Next, create another method, <em>determineGrade()</em>, which takes only one score and return the grade based on the range of the score. (Line 38 -54)
Once the two required methods are created, we are ready to prompt use for input five test scores using Java Scanner class. To use get user input, create a Scanner object (Line 7). Next, use getDouble() method to get an input score and assign it to variables firstScore, secondScore, thirdScore, fourthScore & fifthScore, respectively. Once a score input by user, call determineGrade() method by passing the input score as argument and immediately print out the return grade. (Line 9 - 27)
At last, call calcAverage() method by passing the first test score variables as argument and print out the returned average value. (Line 29).
Network Layer of the TCP/IP protocol
Answer:
D.
Explanation:
Most students would fail to realize that the pictures they use also need citations so that would be the MOST LIKELY to lead to legal consequence.
Answer:
c. honeypot
Explanation:
A honeypot is a computer or a network used to mimic the actual target of a cyberattack. It is also used to detect attacks on the network and divert them from the real network. This is used to gain insight into how cyberattacks are carried out. With such knowledge, robust security systems can be put in place.
The best chart to see the data distribution for the exercise routine would be a pie chart. Using Microsoft Excel, you can input each data point you have for all you exercise routine category, and generate a pie chart which will show you the percentage for each category in comparison to the total.