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GuDViN [60]
2 years ago
13

Consider an improved version of the Vigen ere cipher, where instead of using multiple shift ciphers, multiple mono-alphabetic su

bstitution ciphers are used. That is, the key consists of t random permutations of the alphabet, and the plaintext characters in positions i, t + i, 2t + i, and so on are encrypted using the ith permutation. Show how to break this version of the cipher.
Computers and Technology
1 answer:
anzhelika [568]2 years ago
6 0

Answer:

Kasiski’s method for determining 't' works for Vigenère cipher as well. The only difference is therefore in the second stage of the attack. In the second stage, one needs to build a frequency table for each of the 't' keys, and carry out an attack like on the mono-alphabetic cipher. Given a long enough plaintext, this will work successfully.

Explanation:

Kasiski method is a method of attacking polyalphabetic substitution ciphers such as Vigenère cipher. It is also called Kasiski test or Kasiski examination.

The method involve finding the length of the keyword and then dividing the message into that many simple substitution cryptograms. Frequency analysis could then be used to solve the resulting simple substitution.

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Which telecommunications device is widely used in industries that require closed communication?
Stella [2.4K]

The telecommunications device that  is widely used in industries that require closed communication are walkie-talkies. Correct answer: D

Walkie-talkies are hand-held, portable, two-way radio transceivers which enable secure communication between the two points, without being part of a network.

3 0
2 years ago
Read 2 more answers
When using the Python shell and code block, what triggers the interpreter to begin evaluating a block of code
finlep [7]

Answer:

The answer is "A blank line".

Explanation:

The blank line initiates the interpreter to start examining the line of statements whenever the Python shell as well as the code block are used.  

  • It is also known as the line that has nothing but spaces or lines without texts or a line.  
  • It prints an empty sheet,  which leaves its performance with such a blank line.

5 0
2 years ago
When this program is compiled and executed on an x86-64 Linux system, it prints the string 0x48\n and terminates normally, even
Alexxandr [17]

Answer:

I get 0x55 and this the linking address of the main function.

use this function to see changes:

/* bar6.c */

#include <stdio.h>

char main1;

void p2()

{

printf("0x%X\n", main1);

}

Output is probably 0x0

you can use your original bar6.c with updaated foo.c

char main;

int main() // error because main is already declared

{

  p2();

   //printf("Main address is 0x%x\n",main);

  return 0;

}

Will give u an error

again

int main()

{

  char ch = main;

  p2(); //some value

  printf("Main address is 0x%x\n",main); //some 8 digit number not what printed in p2()

  printf("Char value is 0x%x\n",ch); //last two digit of previous line output

  return 0;

}

So the pain in P2() gets the linking address of the main function and it is different from address of the function main.

Now char main (uninitialized) in another compilation unit fools the compiler by memory-mapping a function pointer on a char directly, without any conversion: that's undefined behavior. Try char main=12; you'll get a multiply defined symbol main...

Explanation:

5 0
1 year ago
What does NOT match with Agile Manifesto?
Butoxors [25]

Answer:

yes

Explanation:

7 0
2 years ago
Make a class Employee with a name and salary. Make a class Manager inherit from Employee. Add an instance variable, named depart
sweet [91]

Answer:

see explaination

Explanation:

class Employee

{

String name;

double salary;

void tostring()

{

System.out.println("Employee:\nName: "+name+"\nSalary: "+salary+"\n");

}

Employee(String n,double s)

{

name=n;

salary=s;

}

}

class Manager extends Employee

{

String department;

void tostring()

{

System.out.println("Manager:\nName: "+name+"\nDepartment: "+department+"\nSalary: "+salary+"\n");

}

Manager(String n,double s,String d)

{

super(n,s);

department=d;

}

}

class Executive extends Manager

{

void tostring()

{

System.out.println("Executive:\nName: "+name+"\nDepartment: "+department+"\nSalary: "+salary+"\n");

}

Executive(String n,double s,String d)

{

super(n,s,d);

}

}

public class test

{

public static void main(String args[])

{

Employee e =new Employee("Neo",12000);

e.tostring();

Manager m =new Manager("Cramster",100000,"Homework");

m.tostring();

Executive ex =new Executive("Chuks",1000000,"Homework");

ex.tostring();

}

}

8 0
1 year ago
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