Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.
The rate of change of a function f(x) over an interval
is given by
Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
is given by
Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
is given by
Therefore, the exponential grows at the same rate as the quadratic in the interval <span>
.</span>
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Answer: .625 (yes he did leave enough
Step-by-step explanation: First you need to divde the fractions( or solve them) ,so 7 divided by 8 and so on Then you take subtract the paint ivan used, if it is less than half than ivan didn't leave enough for his poor sister
but there are other ways if this one is to hard
Answer:
There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.
Also, a probability is unusual if it is lesser than 5%. If it is unusual, it is surprising.
In this problem:
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a standard deviation of 3 minutes, so 
.
We need to find the probability that it takes less than one minute to find a parking space.
So we need to find the pvalue of Z when 
has a pvalue of 0.0228.
There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.
