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valentinak56 [21]
2 years ago
11

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in

order.
Physics
2 answers:
Lana71 [14]2 years ago
5 0

Answer:

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in order.

Step 2: calculate a & b mag

Step 3: calculate x,y components

Step 4: sum vector components

Step 5: calculate magnitude of R

Step 6: calculate direction of R

Maksim231197 [3]2 years ago
4 0

Answer: The next 5 steps are.

step 2: Find the magnitude of vectors.

step 3: Calculate 'x' and 'y' components.

step 4: Sum the above obtained vector components.

step 5: Calculate the magnitude of Resultant Vector.

Step 6: Determine the direction of the resultant vector.

Explanation:

Let the two vectors be 'A' and 'B'.

Let A = x_{1} \hat{i}+y_{1}\hat{j}+z_{1}\hat{k} and B = x_{2} \hat{i}+y_{2}\hat{j}+z_{2}\hat{k}

It is given that, when solving a two dimensional, multi-charge problem, is to define the vectors.

So, step 1 is to define the vectors A and B.

In step 2, we find the magnitude of the vectors by,

|A|=\sqrt{x_1^2+y_1^2+z_1^2}

|B|=\sqrt{x_2^2+y_2^2+z_2^2}

In step 3, we find the components 'x' and 'y'

Then in step 4, we sum the components. Now we get the Resultant vector (R).

In step 5, Calculate the magnitude of 'R' using the above formula to find magnitude.

In step 6, we determine the direction of 'R'.

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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
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This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide.  Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after.  Subtract this from the the system total and you will have the momentum of the other object after the collision.  Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities.  They are vectors, so direction matters.  Typically moving to the right is positive (+) and moving to the left is negative (-).  It is not clear from your question which direction the objects are moving before and after the collision.

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2 years ago
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In a demonstration, a 4.00 cm2 square coil with 10 000 turns enters a larger square region with a uniform 1.50 T magnetic field
Kay [80]

Explanation:

It is given that,

Area of square coil, A=4\ cm^2=0.0004\ m^2

Side of the square, L = 0.02 m

Number of turns, N = 10000

Uniform magnetic field, B = 1.5 T

Speed, v = 100 m/s

An emf is induced in the coil which is given by :

E=NBLv

E=10000\times 1.5\times 0.02\times 100

E = 30000 V

Breakdown voltage of air, V=4000\ V/cm=400000\ V/m

Let d is the gap between the two wires connected to the ends of the coil and still get a spark. So,

Electric field, E'=\dfrac{V}{d}

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2 years ago
A string, 0.28 m long and vibrating in its third harmonic, excites an open pipe that is 0.82 m long into its second overtone res
S_A_V [24]

Answer: 98.

Explanation: it has been stated in the question that sound wave in the string and in the pipe resonated at a specific frequency, this simply implies that the frequency of sound wave in the string equals frequency of sound wave in pipe.

Fs = Fp.

The length (l) of the string is 0.28m and it is vibrating at it third harmonic.

The length of stationary wave on a string at third harmonic is given below as

l = 3λ/2

Where λ = wavelength of sound wave in pipe (λs)

By substituting l = 0.28m into the equation above, we have that

0. 28 = 3λs/2

3λs = 0.28 * 2

3λs = 0.56, λs= 0.56/ 3

λs = 0.187m

Thus the wavelength of wave in the string is 0.187m.

Sound from the string in the pipe is produced at the second overtone ( which is the third harmonic).

Therefore the length of air in the pipe at second overtone ( third harmonic) is given below as

l = 5λp/ 4, we need to get the wavelength of sound in the pipe.

Thus

λp = 4*l/5

λp = 4 * 0.82 / 5

λp = 0.656m.

The velocity of sound waves produced in the pipe is 345m/s thus the frequency of sound in the pipe is gotten using the formulae below

V = fpλp

V= velocity of sound in pipe, fp = frequency of sound in pipe, λp= wavelength of sound in pipe

345 = f / 0.656

fp = 525.92Hz.

As stated in the question, the frequency of sound in pipe is the same as that in string (fp = fs = f) , thus to get the velocity of sound wave in string we use the same formulae of

v = fλ

Where f = frequency of sound in pipe = frequency of sound in string = 525.92Hz.

λ = wavelength of sound in string = 0.187m

Thus v = 525.92 * 0.187 = 98.34 which is closest to 98.

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2 years ago
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.240 rev/s. The magnitude
bazaltina [42]

Explanation:

Given that,

Angular velocity = 0.240 rev/s

Angular acceleration = 0.917 rev/s²

Diameter = 0.720 m

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Using equation of angular motion

\omega_{f}=\omega_{i}+\alpha t

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The angular velocity is 0.426 rev/s.

(b). We need to calculate the tangential speed of the blade

Using formula of  tangential speed

v= r\omega

Put the value into the formula

v = \dfrac{0.720 }{2}\times0.426\times2\pi

v=0.963\ m/s

The tangential speed of the blade is 0.963 m/s.

(c). We need to calculate the magnitude at of the tangential acceleration

Using formula of tangential acceleration

a_{t}=r\alpha

Put the value into the formula

a_{t}=0.36\times0.917\times2\pi

a_{c}=2.074\ m/s^2

The tangential acceleration is 2.074 m/s².

Hence, This is required solution.

4 0
2 years ago
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