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valentinak56 [21]
2 years ago
11

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in

order.
Physics
2 answers:
Lana71 [14]2 years ago
5 0

Answer:

Step 1, when solving a two dimensional, multi-charge problem, is to define the vectors. Please identify the next five steps, in order.

Step 2: calculate a & b mag

Step 3: calculate x,y components

Step 4: sum vector components

Step 5: calculate magnitude of R

Step 6: calculate direction of R

Maksim231197 [3]2 years ago
4 0

Answer: The next 5 steps are.

step 2: Find the magnitude of vectors.

step 3: Calculate 'x' and 'y' components.

step 4: Sum the above obtained vector components.

step 5: Calculate the magnitude of Resultant Vector.

Step 6: Determine the direction of the resultant vector.

Explanation:

Let the two vectors be 'A' and 'B'.

Let A = x_{1} \hat{i}+y_{1}\hat{j}+z_{1}\hat{k} and B = x_{2} \hat{i}+y_{2}\hat{j}+z_{2}\hat{k}

It is given that, when solving a two dimensional, multi-charge problem, is to define the vectors.

So, step 1 is to define the vectors A and B.

In step 2, we find the magnitude of the vectors by,

|A|=\sqrt{x_1^2+y_1^2+z_1^2}

|B|=\sqrt{x_2^2+y_2^2+z_2^2}

In step 3, we find the components 'x' and 'y'

Then in step 4, we sum the components. Now we get the Resultant vector (R).

In step 5, Calculate the magnitude of 'R' using the above formula to find magnitude.

In step 6, we determine the direction of 'R'.

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Andru [333]

Answer:

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

v = velocity of the ball at time t.

Placing the origin at the throwing point, y0 = 0.

Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t²     (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Have a nice day!

4 0
2 years ago
Un pendule est constitue par une masse ponctuelle m= 0,1kg accrocher a un fil sans masse de longueur L = 0,4 m on ecarte ce pend
BabaBlast [244]
I could help
If I know what I was reading I’m sorry I need to translate
3 0
2 years ago
A runner generates 1260 W of thermal energy. If this heat has to be removed only by evaporation, how much water does this runner
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Answer:0.502kg

Explanation:

F4om the relation

Power x time = mass x latent heat of vapourization

P.t=ML

1260 * 15 *60 = M * 22.6 * 10^5

M= 1134000/(22.6 *10^5)

M=0.502kg=502g

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2 years ago
A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel
sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car =2 m/s^2.

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = \frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2

6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2

t =6 sec

So, after 6 seconds, the car will surpass the cycle.  

6 0
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calculate the work done to stretch an elastic string by 40cm if a force of 10N produces an extension of 4cm in it?
Charra [1.4K]
100N is how much work is needed 
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