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Scilla [17]
2 years ago
9

A race car completes the final lap of a race on a 2-kilometer circular track. At the start of the lap, it crosses the line at 60

meters/second. It completes the lap 28.57 seconds later, crossing the line at 85 meters/second. Calculate the displacement and average acceleration of the car within the span of 12 seconds.
A. Displacement is 0 meters, and acceleration is 0.88 meters/second^2.
B. Displacement is 2,000 meters, and acceleration is 1.14 meters/second^2.
C. Displacement is 0 meters, and acceleration is 70.0 meters/second^2.
D. Displacement is 2,000 meters, and acceleration is 80.0 meters/second^2.
E. Displacement is 0 meters, and acceleration is 0.70 meters/second^2.
Physics
1 answer:
Delicious77 [7]2 years ago
6 0
The displacement of an object is the difference between the final position and the initial position. Since the race car rounded the circular track, the displacement is equal to 0 meters. The acceleration, if we assume it to be constant all throughout, should be equal to,
                             (85 m/s - 60 m/s) / (28.57 s) = 0.88 m/s²
Thus, the answer to the question above is letter A. 
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A certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of What is the
Alborosie

Answer:

<em>0.45 mm</em>

Explanation:

The complete question is

a certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of 620 A/ cm^2. What is the diameter of the wire in the fuse?

A) 0.45 mm

B) 0.63 mm

C.) 0.68 mm

D) 0.91 mm

Current in the fuse is 1.0 A

Current density of the fuse when it melts is 620 A/cm^2

Area of the wire in the fuse = I/ρ

Where I is the current through the fuse

ρ is the current density of the fuse

Area = 1/620 = 1.613 x 10^-3 cm^2

We know that 10000 cm^2 = 1 m^2, therefore,

1.613 x 10^-3 cm^2 = 1.613 x 10^-7 m^2

Recall that this area of this wire is gotten as

A = \frac{\pi d^{2} }{4}

where d is the diameter of the wire

1.613 x 10^-7 = \frac{3.142* d^{2} }{4}

6.448 x 10^-7 = 3.142 x d^{2}

d^{2} =\sqrt{ 2.05*10^-7}

d = 4.5 x 10^-4 m = <em>0.45 mm</em>

8 0
2 years ago
1) A capacitor consists of two metal surfaces separated by an electrical insulator with no electrically conductive path through
ki77a [65]

Answer:

Current flows in a resistor-capacitor circuit because of the varying electric field across the plates of a capacitor induced by an AC voltage source <em>(displacement current)</em>

Explanation:

In a capacitor, current does not flow the same way it does in a circuit, that is through conduction. This is because there is a highly resistive material in between the plates of the capacitor. Rather current flows through a phenomenon called displacement current.

Because of change in charge accumulation with time above the plates, the electric field changes causing the displacement current.

Displacement current arises due to the flow of electrons as a result of the varying magnetic fields set up on the plates of the capacitor when supplied with an AC voltage. It is important to note that a DC voltage does not induce any displacement current.

<em>Through this, phenomenon discovered by Maxwell,  current is able to flow in a resistor-capacitor circuit despite the absence of an electrically conductive path through the plates.</em>

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2 years ago
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Answer:

B. Solar energy

Explanation:

The water cycle is driven primarily by the energy from the sun. This solar energy drives the cycle by evaporating water from the oceans, lakes, rivers, and even the soil. Other water moves from plants to the atmosphere through the process of transpiration.

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2 years ago
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Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.
Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

Q_1 = Q_2

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

Q = VA

Where

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Our values are given as

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Since there is continuity we have now that,

V_1A_1 = Q_2

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V_1 = \frac{1.2*10^{-4}}{A_2}

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vitfil [10]

Answer:

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Explanation:

Given;

initial temperature, t₁ = 50 °C

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Therefore, the energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.

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