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natulia [17]
2 years ago
10

A massive tractor rolls down a country road. in a perfectly inelastic collision, a small sports car runs into the machine from b

ehind. (i) which vehicle experiences a change in momentum of larger magnitude
Physics
2 answers:
Helga [31]2 years ago
5 0
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change. 
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
Tresset [83]2 years ago
3 0

Answer:

c) Their momentum changes are the same size.

Explanation:

In order to understand this you need to remember that the momentum is divided equally in the collision, so the correct answer to this is the fact that their momentum will changes the same, because that is how energy is preserved, the thing that could be different is that they are affected different by that momentum, it would probably affect differently the small car and the tractor, it would probably have a lot of impact for the small car.

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Consider the vector b⃗ with magnitude 4.00 m at an angle 23.5∘ north of east. what is the x component bx of this vector? express
BlackZzzverrR [31]
Decomposing the vector b on the x-axis and the y-axis, we get a rectangle triangle where the two sides are bx (x-axis) and by (y-axis), and b is the hypothenuse.
The component in x, bx, is equal to the product between the hypothenuse and the cosine of the angle between b and the x-axis, which is 23.5 ^{\circ}:
b_x = b \cos (23^{\circ})=(4.00 m)(\cos (23^{\circ}))=3.68 m
6 0
2 years ago
A mover hoists a 50 kg box from the ground to a height of 2 m. What was the change in the box's energy
SSSSS [86.1K]

Answer:

980 J

Explanation:

The change in box's energy is equal to its change in gravitational potential energy:

\Delta U = m g \Delta h

where

m = 50 kg is the mass of the box

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta h= 2m is the change in height of the box

Substituting numbers, we find

\Delta U = (50 kg)(9.8 m/s^2)(2 m)=980 J

3 0
2 years ago
2. If a cyclist in the Tour de France traveled southwest a distance of 12,250 meters in one hour, what would the velocity of the
Luda [366]
  • Answer:

<em>12,25 km/h</em>

<em>≈ 3,4 m/s </em>

  • Explanation:

<em>v = d/t</em>

<em>= 12250m/h</em>

<em>= 12,25km/h</em>

<em>or</em>

<em>v = d/t</em>

<em>= 12250m/h</em>

<em>1h = 60m×60s = 3600s</em>

<em>= 12250m/3600s</em>

<em>≈ 3,4 m/s </em>

5 0
2 years ago
The burning of fossil fuels contributes to the addition of greenhouse gases to the atmosphere. These gases trap thermal energy i
denpristay [2]

Answer:

B. there would be a global rise in temperatures

Hence, global warming

Explanation:

hope this helped! :D

5 0
2 years ago
Read 2 more answers
A 10-kilogram box is at static equilibrium, and the downward pull of gravity acting on the box is 98 newtons. What is the minimu
Nikolay [14]
The box is at equilibrium, so the net force on the box is zero (the force of gravity on the box is equal to the force exerted up on the box by the surface on which it rests.)
To pick up the box, our upward force must be greater than the force of gravity on the box (the weight). So, we must lift up the box with a force greater than 98 newtons. :)
4 0
2 years ago
Read 2 more answers
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