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sergeinik [125]
2 years ago
14

What is the direction of the current in the loop as the loop rotates clockwise through the magnetic field from as viewed from th

e top. Answer as you face the loop as it opens towards you.

Physics
2 answers:
Alecsey [184]2 years ago
5 0

Answer:

The direction of the current in the loop is explain with the right hand rule, which is a bout the cross product of two vector, which results is another vector but perpendicular with the initial two.

In this case, the magnetic field has to be perpendicular to the rotation of the current in the loop. Now, you can observe that the magnetic field is towards south in the graph. If we apply right-hand rule, we find that the rotation of the current has to be from west to east, that is, from front of the back of the image.

The image attached shows the right-hand rule.

If the magnetic field were towards North, then the current would rotate in the opposite direction, from East to West.

Hunter-Best [27]2 years ago
4 0

Answer:

by applying the left hand rule you'll find that the direction is as in the photo below

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The chart shows data for four moving objects. A 4 column table with 4 rows. The first column is labeled Object with entries, W,
KatRina [158]

Answer:

y

Explanation:

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3 0
2 years ago
Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea’s reference frame is
BartSMP [9]

Answer:  Sean is standing still, and Rhea is running toward Sean while   kicking the ball

Explanation: Your welcome :)

5 0
2 years ago
the mass of piece of granite is 15.6g when it is suspended can a mass of 5.5g of water is displaced find the dencity of granite
Blababa [14]

Answer:

2836.36 kg/m³

Explanation:

Applying,

Densty of granite(D')/Density of water(D) = weight of granite(W')/weight of water displaced(W)

D'/D = W'/W................... Equation 1

Make D' the subject of the equation

D' = W'D/W............... Equation 2.

From the question,

Given: W' = mg = 9.8(15.6/1000) = 0.15288 N, W = 9.8(5.5/1000) = 0.0539 N, Constant: D = 1000 kg/m³

Substitute these values into equation 2

D' = 1000(0.15288)/0.0539

D' = 2836.36 kg/m³

3 0
1 year ago
Identical guns fire identical bullets horizontally at the same speed from the same height above level planes, one on the Earth a
Natasha_Volkova [10]

Answer:

I. The horizontal distance traveled by the bullet is greater for the Moon.

II. The flight time is less for the bullet on the Earth.

Explanation:

Horizontal distance depends on the initial speed, height and gravity. Bullets have the same initial speed and are shot from the same height. In these conditions horizontal distance only depends on gravity, which is inversely proportional. Therefore, the less gravity the greater the horizontal distance. Gravity slows bullet and causes its impact on the ground. Since gravity is greater in Earth, the bullet hits faster on the earth.

3 0
2 years ago
Read 2 more answers
A block with mass m = 0.250 kg is attached to one end of an ideal spring and moves on a horizontal frictionless surface. The oth
ehidna [41]

Answer:

13.54 N/m

0.6 m

4.37 m/s

32.496 m/s²

Explanation:

m = Mass of block = 0.25 kg

k = Spring constant

A = Amplitude

x = Compression of spring = 0.24 m

a = Acceleration = -13 m/s²

v = Velocity = 4 m/s

The weight of the block and force on spring is equal

ma=-kx\\\Rightarrow k=-\frac{ma}{x}\\\Rightarrow k=-\frac{0.25\times -13}{0.24}\\\Rightarrow k=13.54\ N/m

The spring's force constant is 13.54 N/m

Total energy of the system is given by

E=\frac{1}{2}(mv^2+kx^2)\\\Rightarrow E=\frac{1}{2}(0.25\times 4^2+13.54\times 0.24^2)\\\Rightarrow E=2.39\ J

At maximum displacement v = 0

E=\frac{1}{2}(mv^2+kA^2)\\\Rightarrow E=\frac{1}{2}(0+kA^2)

\\\Rightarrow E=\frac{1}{2}kA^2\\\Rightarrow A=\sqrt{\frac{E2}{k}}\\\Rightarrow A=\sqrt{\frac{2\times 2.39}{13.54}}\\\Rightarrow A=0.6\ m

The amplitude of the motion is 0.6 m

Speed of the block

E=\frac{1}{2}mv_m^2+0\\\Rightarrow v_m=\sqrt{\frac{2E}{m}}\\\Rightarrow v_m=\sqrt{\frac{2\times 2.39}{0.25}}\\\Rightarrow v_m=4.37\ m/s

The maximum speed of the block during its motion is 4.37 m/s

Forces in the spring

ma_m=kA\\\Rightarrow a_m=\frac{kA}{m}\\\Rightarrow a_m=\frac{13.54\times 0.6}{0.25}\\\Rightarrow a_m=32.496\ m/s^2

Maximum magnitude of the block's acceleration during its motion is 32.496 m/s²

5 0
2 years ago
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